Ask question

Ask question

All categories

2 years ago

5

Suppose you start at the origin, move along the x-axis a distance of 6 units in the positive direction, and then move downward p

arallel to the z-axis a distance of 4 units. What are the coordinates of your position

1 answer:

Cerrena [4.2K]2 years ago

3 0

The coordinates of your position are <u>(</u><u>6</u><u>,</u><u> </u><u>0</u><u>,</u><u> </u><u>-4</u><u>)</u>.

You might be interested in

A bakery bakes 15 batches of 29 cupcakes each week. How many individual cupcakes do they make each week?

mylen [45]

Answer:

435 cupcakes baked in one week if that’s what your asking.

3 0

3 years ago

Read 2 more answers

algol [13]

$f\left(\dfrac\beta2\right)=\sin\dfrac\beta2$

Recall the half-angle identity:

$\sin^2\dfrac\beta2=\dfrac{1-\cos\beta}2\implies\sin\dfrac\beta2=\pm\sqrt{\dfrac{1-\cos\beta}2}$

So in order to find $f\left(\dfrac\beta2\right)$ , we only need to know the value of $\cos\beta$ . But there are two possible values. To decide which to take, we use the given information: we know that $\beta$ lies in quadrant III, which means $\pi$ , so $\dfrac\pi2$ , which places $\dfrac\beta2$ in quadrant II. In this quadrant, the sine of angle is positive, and so

$\sin\dfrac\beta2=\sqrt{\dfrac{1-\cos\beta}2}$

$\beta$ is an angle of a ray whose terminal point, $\left(-\dfrac13,y\right)$ lies on the circle $x^2+y^2=1$ . The $x$ -coordinate is all we need to know in order to find that $\cos\beta=-\dfrac13$ . So,

$\sin\dfrac\beta2=\sqrt{\dfrac{1-\left(-\frac13\right)}2}=\sqrt{\dfrac46}=\dfrac{\sqrt2}{\sqrt3}=\dfrac{\sqrt6}3$

6 0

3 years ago

Solve the inequality.<br> - 27> -3(4x-3)

Readme [11.4K]

The answer is 3>x because first you divide by three on both sides leaving you with positive 9>4x-3 then you add three on both side leaving you with 12>4x and lastly you divide four on bottom sides ending with 3>x.

4 0

3 years ago

During your cycling trip, you and your friends often stayed in hostels. The prices of these are listed below.

saw5 [17]

Answer:

$26.3 night-time rest days

Range is $33.19

Step-by-step explanation:

We need to find the mean of the standard cost to find the night-time rest days:

$Mean=\frac{\text{sum of the observations}}{\text{Number of observations}}$

So, the required mean is : $\frac{22.45+18.55+24.50+11.20+??}{5}=20.60$

$\frac{76.7+?}{5}=20.60$

$\Rightarrow 76.7+?=103$

$\Rightarrow ?=26.3$

After simplification we will get the night-time rest days price which is: $26.3

Now, we will find the range in cost of stays in standard price and with breakfast price which is difference between the maximum cost minus the lowest cost

So, the sum of Standard cost is: $103

And the sum of Breakfast price cost is: $136.19

So, the required range is: $136.19-$103=$33.19

4 0

3 years ago

Can someone help me with this problem pleaseeee :(

Andrej [43]

Answer:

2/7

Step-by-step explanation:

6 large fish and 8 small fish (half of the them are red = 4)

total fish 6 + 8 = 14 fishes

probability that one fish is one small and red fish is

there are 4 small and red fish

= 4c1 / 14c1

= (4! / (1! (4 - 1)! ) / (14! / (1! (14-1)! )

= 4/14

= 2/7

6 0

3 years ago