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inessss [21]
1 year ago
15

F f(x) = 3x + 2 and g(x) = x2 + 1, which expression is equivalent to (f circle g) (x)?

Mathematics
1 answer:
seraphim [82]1 year ago
8 0

hi

f°g  mean apply  g(x) and  then use result of  g(x) as  "x" in f(x)

so as  g(x) = x² +1   and  f(x) = 3x+2

so if we call  g(x)   X  we have  

f( X) =  3 X +2

now we replace  " X"  for it's value

f(X) =  3 ( x² +1) +2

f(X) =  3x² +3 +2

f(X) = 3x² +5

so  f°g = 3x² +5

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Find the linear approximation of the function g(x) = 5 1 + x at a = 0. g(x) ≈ use it to approximate the numbers 5 0.95 and 5 1.1
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Differentiating the function

... g(x) = 5^(1+x)

we get

... g'(x) = ln(5)·5^(1+x)

Then the linear approximation near x=0 is

... y = g'(0)(x - 0) + g(0)

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With numbers filled in, this is

... y ≈ 8.047x + 5 . . . . . linear approximation to g(x)

Using this to find approximate values for 5^0.95 and 5^1.1, we can fill in x=-0.05 and x=0.1 to get

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3 years ago
2. En el sobre de un jugo instantáneo aparece la siguiente información: “prepare un delicioso litro de jugo de naranja”. Si con
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2) 200 mL

3) 0.2 kg

Step-by-step explanation:

2)

In this problem, we know that:

- With 1 liter of juice, we can fill a total of 5 cups

So we know that the total volume of 5 cups is equal to

V = 1 L

This means that the volume of each cup is equal to the total volume divided by the number of cups (5), therefore:

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And keeping in mind the equivalence between liters and milliliters:

1 L = 1000 mL

This means that the capacity of each cup is

V_1=0.2 L \cdot 1000 mL/L = 200 mL

3)

Here we want to find the mass contained in each cup.

We know that the mass of a substance is related to each volume by the equation

d=\frac{m}{V}

where

d is the density

m is the mass

V is the volume

In this problem, we have:

V = 0.2 L is the volume of juice in each cup

d=1kg/L is the density of juice (assuming it is the same as the density of water)

So, the mass of juice in one cup is:

m=dV=(1)(0.2)=0.2 kg

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