Answer:
Year 1: $1,100
Year 2: $ 1,210
Step-by-step explanation:
The given expresion is:
This represents the value of a $1000 investment that earns 10% interest per year, compounded annually for 2 years.
To find the value of a $1000 investment at the end of the first year , we substitute t=1.
To find the value of a $1000 investment at the end of the second year , we substitute t=2.
Let's represent the number of hours with the variable 'h' (or whatever letter you want it to be):
265 + 48h = 553
Substract both sides by 265:
48h = 288
Divide:
h = 6
6 hours of labor was spent
-63+14x
7(-9+2x)=7(-9)+7(2x)=-63+14x
the 3 statement is true