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2 years ago

NEED HELP DUE IN 2 MINUTES!!!!

Mathematics

1 answer:

Natalija [7]2 years ago

5 0

B. 40 centimeters long

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3 years ago

the sum of three numbers is 55. the second number is twice the first and the third number is five less than the second. What are

ArbitrLikvidat [17]

Let the first number be = x

Then the second number = 2x

The third number = 2x - 5

Their sum = 55

This can be written in an equation as =

x + 2x + 2x - 5 = 55

= x + 2x + 2x = 55 + 5 ( transposing -5 from LHS to RHS changes -5 to +5 )

= x + 2x + 2x = 60

= 5x = 60

= x = 60 ÷ 5 ( transposing ×5 from LHS to RHS changes ×5 to ÷5 )

= x = 12

The first number = x = 12

The second number = 2x = 2 × 20 = 24

The third number = 2x - 5 = 24 - 5 = 19

Therefore , the three numbers are 12 , 24 and 19 .

5 0

3 years ago

How do I solve for x

Alchen [17]

Greetings!

To find the length of any side of a right triangle, you can use the Pythagorean Thereom. It states that the squares of two sides are equal to the square of the hypotenuse:
$a^2+b^2=c^2$

Input the information from the diagram into the formula:
$(x)^2+(x+7)^2=(13)^2$

Expand each term:
$(x)^2+(x+7)^2=(13)^2$

$x^2+((x+7)(x+7))=169$

$x^2+(x(x+7)+7(x+7))=169$

$x^2+x^2+7x+7x+49=169$

Combine like terms:
$2x^2+14x+49=169$

Add -169 to both sides:
$(2x^2+14x+49)+(-169)=(169)+(-169)$

$2x^2+14x-120=0$

Factor out the Common Term (2):
$2(x^2+7x-60)=0$

Factor the Complex Trinomial:
$2(x^2-5x+12x-60)=0$

$2(x(x-5)+12(x-5))=0$

$2(x-5)(x+12)=0$

Set Factors to equal 0:
$x-5=0$

$x=5$

or

$x+12=0$

$x=-12$

However, since we are solving for the side length, the only possible answer is 5 (a shape can't have a side with a negative length.)

The Solution Is:
$\boxed{x=5}$

I hope this helped!
-Benjamin

6 0

3 years ago