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2 years ago

Collecting ducts within the kidney tubules cut in cross section would reveal what type of epithelium?

1 answer:

3 0

Simple cuboid epithelium found in glandular kidney tubules. This is observed in the lining of the kidney tubules and ducts of glans. Nucleus of tall column like cells trend to be elongated and found in the basal end of the cells.

It is composed of single layer that is relatively ,larger surface area, which is allow them to absorption and secretion of substances like water and salt from the kidney and hormones which are produced by the glands.

Simple epithelium tissues are specialized for diffusion and absorption. This is also found in lining the cavities of body such as pericardial , peritoneal and pleurae.

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In a population of plants, the allele for long stems (S) is completely dominant over the allele for short stems (s). If 35% of t

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The correct answer would be 48 percent.

It can be solved by using the Hardy-Weinberg equation.

p² + 2pq+ q² = 1

p + q = 1

where, p² represents homozygous dominant's frequency that is, SS in this case,

q² represents homozygous recessive's frequency that is, ss in this case,

2pq represents heterozygous dominant's frequency that is, Ss in this case.

p represents dominant allele's frequency and q represents the recessive allele's frequency.

Now, the percentage of homozygous recessive or short stems is 35%. Therefore, the frequency of homozygous recessive would be 0.35.

Thus, the value of q² = 0.35

So, q = $\sqrt{0.35}$ = 0.59 which is approximately equals to 0.6.

As p + q = 1 so, q = 1 - 0.6 = 0.4

The frequency of heterozygous (Ss) = 2pq = 2(0.6)(0.4) = 0.48

Hence, the frequency of heterozygous would be 48 percent.

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