Answer:
A compiled language is a programming language whose implementations are typically compilers and not interpreters. In this language, once the program is compiled it is expressed in the instructions of the target machine. There are at least two steps to get from source code to execution. While, an interpreted language is a programming language whose implementations execute instructions directly and freely, without previously compiling a program into machine-language instructions. While in this language, the instructions are not directly executed by the target machine. There is only one step to get from source code to execution.
I hope this helps.
The same thing as if you do it once
I would vote for D since you can adjust picture positioning and wrapping. A is BS, B and C are not true.
Answer:
A
Explanation:
The value will be the original stored in the int variables. This is because the method swap(int xp, int yp) accepts xp and yp parameters by value (They are passed by value and not by reference). Consider the implementation below:
public class Agbas {
public static void main(String[] args) {
int xp = 2;
int yp = xp;
swap(xp,yp); //will swap and print the same values
System.out.println(xp+", "+yp); // prints the original in values 2,2
int xp = 2;
int yp = 5;
swap(xp,yp); // will swap and print 5,2
System.out.println(xp+", "+yp); // prints the original in values 2,5
}
public static void swap(int xp, int yp){
int temp = xp;
xp = yp;
yp = temp;
System.out.println(xp+", "+yp);
}
}
