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PilotLPTM [1.2K]
2 years ago
5

What is string literal in Java?

Computers and Technology
1 answer:
4vir4ik [10]2 years ago
8 0

Answer:

A string literal in Java is basically a sequence of characters from the source character set used by Java programmers to populate string objects or to display text to a user. These characters could be anything like letters, numbers or symbols which are enclosed within two quotation marks.

Explanation:

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Zarrin [17]
Some examples of environmental technology is recycling.
3 0
3 years ago
The waterfall model and spiral model are variations of SDLC. Do some research to find out what they are and explain how these mo
Radda [10]

Waterfall model and spiral model are used in software development life cycle or SDLC. Any software development process follows one of these models depending on the type of software and the requirements of the customer.

Waterfall model

This model is called as sequential model since it works in stages. The output of first stage becomes the input of the second stage.

The errors of the first stage can be rectified only when it is completed. This is time consuming and makes the process lengthy. Stage 1 is completed before stage 2 begins.

The six stages involved in waterfall model are Requirement Gathering and analysis, System Design, Implementation, Integration and Testing, Deployment of system, and Maintenance.

Spiral model

This model is implemented in iterations. It is also called evolutionary model.  

Initially a prototype of the system is prepared. Then, it is followed by development of small parts of the system.

These smaller parts are then assembled to produce the final system.

The four stages which form the spiral model are Identification, Design, Development and Evaluation and Risk Analysis.

The differences between the two models are summarized below.

1. Waterfall model works in linear method. Spiral model follows evolutionary method.

2. Errors and risks are discovered/ rectified after the stage is over. Errors and risks are discovered/ rectified earlier.

3. Waterfall model is suitable for small projects. Spiral model is suitable for large projects.

4. Requirements identification and planning is the initial stage in the waterfall model. Requirements identification and planning is done when needed, in the spiral model.

5. Waterfall model allows little to no flexibility in the system. Spiral model allows flexibility in the system.

6. Low flexibility makes the waterfall model more risky. High flexibility makes the spiral model less risky.

7. Waterfall model, overall, takes less time since requirements are clear. Spiral model is implemented when the requirements of the system are not clear and become clear through prototypes.

8 0
3 years ago
A digital computer has a memory unit with 16 bits per word. The instruction set consists of 72 different operations. All instruc
OLga [1]

Answer:

a. 7 bits b. 9 bits c. 1 kB d. 2¹⁶ - 1

Explanation:

a. How many bits are needed for the opcode?

Since there are 72 different operations, we require the number of bits that would contain 72 different operations. So, 2ⁿ ≥ 72

72 = 64 + 8 = 2⁶ + 8

Since n must be an integer value, the closest value of n that would contain 72 different operations is n = 7. So, 2⁷ = 128

So, we require 7 bits for the opcode.

b. How many bits are left for the address part of the instruction?

bits left = bits per word - opcode bit = 16 - 7 = 9 bits

c. What is the maximum allowable size for memory?

Since there are going to be 2⁹ bits to addresses each word and 16 bits  for each word, the maximum allowable size for memory is thus 2⁹ × 16 = 512 × 16 = 8192 bits.

We convert this to bytes

8192 bits × 1 byte/8 bits = 1024 bytes = 1 kB

d. What is the largest unsigned binary number that can be accommodated in one word of memory?

Since the number go from 0 to 2¹⁶, the largest unsigned binary number that can be accommodated in one word of memory is thus

2¹⁶ - 1

6 0
3 years ago
List three things to be safer online.
kenny6666 [7]

Answer:

1. do not give out your age

2. don't use your real name unless you are supervised

3.dont put all your information out there

5 0
2 years ago
In c++
Elodia [21]

Answer:

class studentType: public personType

{

public:

virtual void print() = 0;

virtual void calculateGPA() = 0;

void setID(long id) {

studentId = id;

}

void setCourses(const string c[], int noOfC) {

noOfCourses = noOfC;

for (int i=0; i<noOfCourses; i++) {

courses[i] = c[i];

}

}

void setGrades(const char cG[], int noOfC) {

noOfCourses = noOfC;

for (int i=0; i<noOfCourses; i++) {

coursesGrade[i] = cG[i];

}

}

long getID() {

return studentId;

}

string* getCourses() {

return courses;

}

char* getGrades() {

return coursesGrade;

}

studentType(string fName = "", string lastName = "",

long id = 0, string c[] = NULL, char cG[] = NULL, int noOfC = 0);

private:

long studentId;

string courses[6];

char coursesGrade[6];

int noOfCourses;

};

Explanation:

Code rewritten

5 0
2 years ago
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