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Rainbow [258]
4 years ago
15

In Load/Store Architecture, memory is only referenced by load and store instructions.

Computers and Technology
1 answer:
11111nata11111 [884]4 years ago
4 0

Answer:True

Explanation: Load-store architecture is the architecture in the computer system field that  contains the instruction collection.These sets of the instructions are dived in the two parts named as the ALU(arithmetic and logical) operation section and memory access section.

The ALU operation part handles the arithmetic calculation and evaluation between the registers whereas the memory access part handles the load and store actions only between the register and memory.Thus , the given statement is true.

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Dallas is an analyst at an online retailer. He is great at creating representative diagrams showing the relationships between cu
dimulka [17.4K]

Answer:

The correct answer to the following question will be "Abstract Reasoning".

Explanation:

  • Abstract reasoning depends on the ability to interpret facts, to identify correlations and interactions and to resolve the problems at a deep, conceptual level.
  • To be able to construct hypotheses about both the existence of events and concepts require abstract reasoning capabilities.

This suggests, therefore, that Dallas has this ability.

4 0
4 years ago
What is the importance of using the proper markup language?
Klio2033 [76]

the answer is D. without the right tags the content wont be accurately indexed

3 0
4 years ago
Read 2 more answers
Given parameters b and h which stand for the base and the height of an isosceles triangle (i.e., a triangle that has two equal s
schepotkina [342]

Answer:

The area of the triangle is calculated as thus:

Area = 0.5 * b * h

To calculate the perimeter of the triangle, the measurement of the slant height has to be derived;

Let s represent the slant height;

Dividing the triangle into 2 gives a right angled triangle;

The slant height, s is calculated using Pythagoras theorem as thus

s = \sqrt{b^2 + h^2}

The perimeter of the triangle is then calculated as thus;

Perimeter = s + s + b

Perimeter = \sqrt{b^2 + h^2} + \sqrt{b^2 + h^2} +b

Perimeter = 2\sqrt{b^2 + h^2} + b

For the volume of the cone,

when the triangle is spin, the base of the triangle forms the diameter of the cone;

Volume = \frac{1}{3} \pi * r^2 * h

Where r = \frac{1}{2} * diameter

So, r = \frac{1}{2}b

So, Volume = \frac{1}{3} \pi * (\frac{b}{2})^2 * h

Base on the above illustrations, the program is as follows;

#include<iostream>

#include<cmath>

using namespace std;

void CalcArea(double b, double h)

{

//Calculate Area

double Area = 0.5 * b * h;

//Print Area

cout<<"Area = "<<Area<<endl;

}

void CalcPerimeter(double b, double h)

{

//Calculate Perimeter

double Perimeter = 2 * sqrt(pow(h,2)+pow((0.5 * b),2)) + b;

//Print Perimeter

cout<<"Perimeter = "<<Perimeter<<endl;

}

void CalcVolume(double b, double h)

{

//Calculate Volume

double Volume = (1.0/3.0) * (22.0/7.0) * pow((0.5 * b),2) * h;

//Print Volume

cout<<"Volume = "<<Volume<<endl;

}

int main()

{

double b, h;

//Prompt User for input

cout<<"Base: ";

cin>>b;

cout<<"Height: ";

cin>>h;

//Call CalcVolume function

CalcVolume(b,h);

//Call CalcArea function

CalcArea(b,h);

//Call CalcPerimeter function

CalcPerimeter(b,h);

 

return 0;

}

3 0
3 years ago
Edhesive assignment 4
Agata [3.3K]

Answer:

nrToCheck = int(input("How many numbers do you need to check? "))

nrEven = 0

nrOdd = 0

for i in range(nrToCheck):

 number = int(input("Enter number: "))

 if (number % 2):

   nrOdd = nrOdd + 1

   print("{} is an odd number".format(number))

 else:

   nrEven = nrEven + 1

   print("{} is an even number".format(number))

print("You entered {} even number(s).".format(nrEven));

print("You entered {} odd number(s).".format(nrOdd));

7 0
3 years ago
The sum of these 9 numbers is 36. 2, 2, 6, 2, 1, 8, 7, 5, 3 What is the mean of these 9 numbers?
fiasKO [112]

Answer:

4

Explanation:

The mean is the sum divided by the count of numbers, so 36/9 = 4

6 0
2 years ago
Read 2 more answers
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