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jenyasd209 [6]
2 years ago
9

Which represents an exterior angle of triangle ABF? ∠BAD ∠AFE ∠CAD ∠CAB

Mathematics
1 answer:
Oxana [17]2 years ago
6 0

The angle that represents an exterior angle of the given triangle is: D. ∠CAB.

<h3>What is an Exterior Angle of a Triangle?</h3>

An exterior angle of a triangle is the angle that is located outside a triangle on an extended adjacent side of the triangle.

In the image given, and considering the options we have, ∠CAB is located outside a triangle ABF on an extended adjacent side CF of the triangle.

Therefore, the answer is: D. ∠CAB.

Learn more about the exterior angle of a triangle on:

brainly.com/question/17972372

#SPJ1

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Dmitry_Shevchenko [17]

Answer:

A = 216 cm^2

P = 80 cm

Step-by-step explanation:

l = 12

w = 18

As the object is rectangular, the area is height * width and the perimeter is

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12 * 18 = 216 U^2   U = unit of measurement, I would presume for a poster you use cm so its 216 cm^2

12 + 18 = 40

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A cylindrical 2014-t6 aluminum alloy bar is subjected to compression-tension stress cycling along its axis; results of these tes
Pani-rosa [81]

Complete part of Question:

Assume a factor of safety of 3.0

The Maximum stress versus logarithm of the number of cycles to fatigue failure curve for 2014-T6 Aluminium bar is attached to this solution

Answer:

The maximum allowable load amplitude is 6403.33 N

Step-by-step explanation:

diameter of the bar, d = 12 mm

d = 0.012 m

Cross sectional area of the bar, A = πd²/4

A = π*0.012²/4

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From the Maximum stress versus logarithm of the number of cycles to fatigue failure for 2014-T6 Aluminium bar attached to this solution;

At 10⁷ cycles, Maximum stress, S = 170 MPa

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\sigma = S/N\\\sigma = \frac{170 * 10^{6} }{3} \\\sigma = 56.67 * 10^{6} N/m^{2}

The tensile stress is also given by:

\sigma = F/A\\\sigma = F/0.000113

F/0.000113 = 56.67 * 10⁶

F = 56.67 * 10⁶ * 0.000113

F = 6403.33 N

The maximum allowable load amplitude is 6403.33 N

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