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BaLLatris [955]
3 years ago
13

I made a z00m join if you want Meeting ID 434-341-8872 Password 5nAqMW

Mathematics
2 answers:
geniusboy [140]3 years ago
8 0

Answer:

ok

Step-by-step explanation:

I need points too soon. hi

Misha Larkins [42]3 years ago
6 0

Answer:

no

Step-by-step explanation:

no thanks <3

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I need answers please ;-; i HATE MAAAAAAAAAAAAAAAATH
zlopas [31]

Answer:

y = 2x

Step-by-step explanation:

if 13 inches of snow has fallen over 6.5 hours, you just divide 13 by 6.5 to get the amount that has fallen each hour (2 inches)

6 0
3 years ago
Read 2 more answers
If 8(x) is the inverse of f(x) and f(x) = 4x + 12, what is g(x)?
Novay_Z [31]

Answer:

g(x)=\frac{x-12}{4}

Step-by-step explanation:

To find the inverse of y=4x+12, all you need to is swap x an y and then remake y the subject.

y=4x+12

Swap x and y:

x=4y+12

Solve for y:

Subtracting 12 on both sides:

x-12=4y

Dividing 4 on both sides:

\frac{x-12}{4}=y

So g(x)=\frac{x-12}{4}

6 0
3 years ago
Read 2 more answers
Need help plz<br> Expand and combine like terms.<br><br> (5a³−6a²)(5a³+6a²)=
nignag [31]

Answer:

=25a6−36a4

Step-by-step explanation:

=(5a3+−6a2)(5a3+6a2)

=(5a3)(5a3)+(5a3)(6a2)+(−6a2)(5a3)+(−6a2)(6a2)

=25a6+30a5−30a5−36a4

=25a6−36a4

7 0
3 years ago
A candy company makes boxes of chocolates. Each box has 32 chocolates total. Of those 32 chocolates 14 of them have nuts. If the
Agata [3.3K]

Answer: 266

Step-by-step explanation: This is a ratio problem. If there are 14 chocolates with nuts out of every 32 chocolates, you can use this as a ratio and set it up as a proportion.

(1) 14 chocolates w/ nuts / 32 chocolates = n chocolates / 608 chocolates

(2) Solve for n: 8,512 = 32n; n = 266

7 0
3 years ago
Find the slop from the given equation. 2x + 4y + 7 = 0
antiseptic1488 [7]

The slope of the line would be -1/2.

To find the slope we need to make the line in the form y = mx + b:

2x + 4y + 7 = 0

2x + 4y = -7

4y = -2x - 7

÷ 4

y = (-2/4)x - (7/4)

-2/4 simplifies to -1/2.

I hope this helps!


6 0
3 years ago
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