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3 years ago

I made a z00m join if you want Meeting ID 434-341-8872 Password 5nAqMW

Mathematics

2 answers:

geniusboy [140]3 years ago

8 0

Answer:

Step-by-step explanation:

I need points too soon. hi

Misha Larkins [42]3 years ago

6 0

Answer:

Step-by-step explanation:

no thanks <3

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Jayla recently accepted a new job earning $15.50 per hour. Last month, Jayla earned $2294 after four weeks of work. How many hou

Alona [7]

15.50h = 2294
h= 148 hours

4w = 148

w= 37 hours each week

5 0

3 years ago

A study of long-distance phone calls made from General Electric Corporate Headquarters in Fairfield, Connecticut, revealed the l

Anna [14]

Answer:

a) 0.4452

b) 0.0548

c) 0.0501

d) 0.9145

e) 6.08 minutes or greater

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 4.7 minutes

Standard Deviation, σ = 0.50 minutes.

We are given that the distribution of length of the calls is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

a) P(calls last between 4.7 and 5.5 minutes)

$P(4.7 \leq x \leq 5.5) = P(\displaystyle\frac{4.7 - 4.7}{0.50} \leq z \leq \displaystyle\frac{5.5-4.7}{0.50}) = P(0 \leq z \leq 1.6)\\\\= P(z \leq 1.6) - P(z$

$P(4.7 \leq x \leq 5.5) = 44.52\%$

b) P(calls last more than 5.5 minutes)

$P(x > 5.5) = P(z > \displaystyle\frac{5.5-4.7}{0.50}) = P(z > 1.6)\\\\P( z > 1.6) = 1 - P(z \leq 1.6)$

Calculating the value from the standard normal table we have,

$1 - 0.9452 = 0.0548 = 5.48\%\\P( x > 5.5) = 5.48\%$

c) P( calls last between 5.5 and 6 minutes)

$P(4.7 \leq x \leq 5.5) = P(\displaystyle\frac{5.5 - 4.7}{0.50} \leq z \leq \displaystyle\frac{6-4.7}{0.50}) = P(1.6 \leq z \leq 2.6)\\\\= P(z \leq 2.6) - P(z$

$P(5.5 \leq x \leq 6) = 5.01\%$

d) P( calls last between 4 and 6 minutes)

$P(4 \leq x \leq 6) = P(\displaystyle\frac{4 - 4.7}{0.50} \leq z \leq \displaystyle\frac{6-4.7}{0.50}) = P(-1.4 \leq z \leq 2.6)\\\\= P(z \leq 2.6) - P(z$

$P(4 \leq x \leq 6) = 91.45\%$

e) We have to find the value of x such that the probability is 0.03.

P(X > x)

$P( X > x) = P( z > \displaystyle\frac{x - 4.7}{0.50})=0.03$

$= 1 -P( z \leq \displaystyle\frac{x - 4.7}{0.50})=0.03$

$=P( z \leq \displaystyle\frac{x - 4.7}{0.50})=0.997$

Calculation the value from standard normal z table, we have,

P(z < 2.75) = 0.997

$\displaystyle\frac{x - 4.7}{0.50} = 2.75\\x = 6.075 \approx 6.08$

Hence, the call lengths must be 6.08 minutes or greater for them to lie in the highest 3%.

8 0

3 years ago

Jane computes the variance for a set of data and gets the correct answer of 16. What is the standard deviation for this same set

PilotLPTM [1.2K]

The standard deviation of a dataset is the square root of the variance.

The standard deviation of the same set of data is 4

The variance is given as:

$\sigma^2 = 16$

Take the square root of both sides to calculate the standard deviation

$\sigma = \sqrt{\sigma^2$

Substitute 16 for $\sigma^2$ .

So, we have:

$\sigma = \sqrt{16}$

Take the positive square root of 16

$\sigma = 4$

Hence, the standard deviation of the same set of data is 4

Read more about standard deviations at:

brainly.com/question/475676

3 0

2 years ago

P = R - C/N Solve for C

RSB [31]

Start by subtracting r, then divide -N That equals out to C = RN - PN , It's a bit Confusing lol<span />

4 0

3 years ago

Which is the definition of x-intercept? the value where the line crosses the x-axis the value where the line crosses the y-axis

Naily [24]

The answer is the value where the line crosses the x-axis.
or simply you can put y= 0 to find x-intercept. or if you want to find y-intercept put x=0 to find its intercepts

5 0

3 years ago