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BaLLatris [955]
3 years ago
13

I made a z00m join if you want Meeting ID 434-341-8872 Password 5nAqMW

Mathematics
2 answers:
geniusboy [140]3 years ago
8 0

Answer:

ok

Step-by-step explanation:

I need points too soon. hi

Misha Larkins [42]3 years ago
6 0

Answer:

no

Step-by-step explanation:

no thanks <3

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8 0
3 years ago
Please solve the eqution<br> Cos4x + cos2x - 2 =0
horrorfan [7]

cos4x = cos2x

We know that:

cos2x = 1-2cos^2 x

==> cos4x = 1-2cos^2 (2x)

Now substitute:

==> 1-2cos^2 (2x) = cos2x

==> 2cos^2 (2x) + cos2x - 1 = 0

Now factor:

==> (2cos2x -1)(cos2x + 1) = 0

==> 2cos2x -1 = 0 ==> cos2x =1/2 ==> 2x= pi/3

==> x1= pi/6 , 7pi/6

==> x1= pi/6 + 2npi

==> x2= 7pi/6 + 2npi

==> cos2x = -1 ==> 2x= pi ==> x3 = pi/2 + 2npi.

<span>==> x= { pi/6+2npi, 7pi/6+2npi, pi/2+2npi}</span>

6 0
3 years ago
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meriva
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8 0
2 years ago
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natta225 [31]

Answer:

I believe the answer it 0.1875

6 0
3 years ago
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natima [27]

Answer:

12.99km

Step-by-step explanation:

Using the formula

C=2(pi)(r)

7 0
2 years ago
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