Question

Please help thanks !

Answer 1

Answer:

point slope form: y-3=$-\frac{3}5}$(x+2)

slope-intercept form: y=$-\frac{3}{5}$x+$\frac{9}{5}$

Step-by-step explanation:

so to find point-slope form, you first have to find the slope of the line

--slope =$\frac{y_{2}-y_{1} }{x_{2} -x_{1} }$=$\frac{0-3}{3+2} =-\frac{3}{5}$ (you have to use the two points shown: (-2,3) and (3,0) to plug in for y1, y2, x1, and x2 to find the slope.)

so your slope is $-\frac{3}{5}$.

Now all you have to do is use one of the points (-2,3) to sub in for y1 and x1 in the point-slope form equation.

Therefore, you get y-3=$-\frac{3}{5}$(x+2) for point-slope form.

Now for slope-intercept form, you already have the slope because you found it to complete the equation for point slope form

slope = $-\frac{3}{5}$

Now slope intercept form is y=mx+b, where m is the slope and b is the y-intercept.

So, far we have y=$-\frac{3}{5}$x+b

the easiet point to use for the x and y values is (3,0)

so, lets substitute: 0=$-\frac{3}{5}$(3)+b, which becomes 0=$-\frac{9}{5}$+b

add $-\frac{9}{5}$ to both sides to get b=$\frac{9}{5}$

Now you have both the slope and the y-intercept so you can now write the line in slope-intercept form.

You get $y=-\frac{3}{5}x +\frac{9}{5}$.