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AleksandrR [38]
3 years ago
11

Please help thanks !

Mathematics
1 answer:
Sergio039 [100]3 years ago
5 0

Answer:

point slope form: y-3=-\frac{3}5}(x+2)

slope-intercept form: y=-\frac{3}{5}x+\frac{9}{5}

Step-by-step explanation:

so to find point-slope form, you first have to find the slope of the line

--slope =\frac{y_{2}-y_{1} }{x_{2} -x_{1} }=\frac{0-3}{3+2} =-\frac{3}{5} (you have to use the two points shown: (-2,3) and (3,0) to plug in for y1, y2, x1, and x2 to find the slope.)

so your slope is -\frac{3}{5}.

Now all you have to do is use one of the points (-2,3) to sub in for y1 and x1 in the point-slope form equation.

Therefore, you get y-3=-\frac{3}{5}(x+2) for point-slope form.

Now for slope-intercept form, you already have the slope because you found it to complete the equation for point slope form

slope = -\frac{3}{5}

Now slope intercept form is y=mx+b, where m is the slope and b is the y-intercept.

So, far we have y=-\frac{3}{5}x+b

the easiet point to use for the x and y values is (3,0)

so, lets substitute: 0=-\frac{3}{5}(3)+b, which becomes 0=-\frac{9}{5}+b

add -\frac{9}{5} to both sides to get b=\frac{9}{5}

Now you have both the slope and the y-intercept so you can now write the line in slope-intercept form.

You get y=-\frac{3}{5}x +\frac{9}{5}.

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