Answer:
1/36
Step-by-step explanation:
When the coefficient is 1, the function has zeros at -3 and -5, one horizontal unit from the vertex. You want to move the zero to (2, 0), which is 6 units from the vertex. To achieve a horizontal stretch by a factor of 6, the value of x in the function must be replaced by x/6. That would make the coefficient of x^2 be (1/6)^2 = 1/36.
The coefficient of the squared term is 1/36.
3x² -16x-12 =0
We can solve this equation using formula.
a=3, b=-16, c=-12
2x*2 + 6x + 80
First we have to use distribution property
2(x*2 + 3x + 40)=0
Divide 2 to both sides
X*2 + 3x + 40=0
Multiply -1
-x*2 -3x-40=0
Add two numbers to get 3x
Multiply same two numbers that you add to get 40x*2
Add
-8x+5x= -3x
Multiply
-8x . 5x= -40x*2
-x*2-8x+5x-40
(X*2-8x) + (5x-40)
X(x-8)+ 5(X-8)
Common factor
(X-8)(x+5)
This would help you!
Answer:
(7, -6)
Step-by-step explanation:
You want to find point X on the segment from A to B such that ...
(X -A)/(B -X) = 3/2
2(X -A) = 3(B -X) . . . . . . cross multiply
2X -2A = 3B -3X . . . . . eliminate parentheses
5X = 2A +3B . . . . . . . . add 3X +2A
X = (2A +3B)/5 . . . . . . . divide by 5
Filling in the given points for A and B, we have ...
X = (2(4, -3) +3(9, -8))/5 = (8+27, -6-24)/5 = (35, -30)/5
X = (7, -6)
The point that divides the segment in the proportions 3:2 is (7, -6).
Answer:73
Step-by-step explanation: