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erastovalidia [21]
2 years ago
15

What is the quotient?

Mathematics
1 answer:
Helen [10]2 years ago
7 0

The answer choice which represents the quotient of the expression given is; 1/(t+4)².

<h3>Which answer choice represents the quotient?</h3>

It follows from the task content that the quotient which is to be evaluated is;

(t+3)/t+4) ÷ (t²+7t +12)

The quotient can therefore be evaluated as follows;

= (t+3)/t+4) ÷ (t+3)(t+4)

= (t+3)/t+4) × 1/(t+3)(t+4)

= 1/(t+4) × 1/(t+4)

= 1/(t+4)².

Read more on factorisation;

brainly.com/question/52959

#SPJ1

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Students in a zoology class took a final exam. They took equivalent forms of the exam at monthly intervals thereafter. After t​
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Answer:

a. 73; b. 48.9; c. 2; d. 33.8; e. 73

Step-by-step explanation:

Assume the function was

S(t)= 73 - 15 ln(t + 1), t  ≥ 0

a. Average score at t = 0

S(0) = 73 - 15 ln(0 + 1) = 73 - 15 ln(1) = 73 - 15(0) =73 - 0 = 73

b. Average score at t = 4

S(4) = 73 - 15 ln(4 + 1) = 73 - 15 ln(5) = 73 - 15(1.61) =73 - 24.14 = 48.9

c. Average score at t =24

S(24) = 73 - 15 ln(24 + 1) = 73 - 15 ln(25) = 73 - 15(3.22) =73 - 48.28 = 24.7

d. Percent of answers retained

At t = 0. the students retained 73 % of the answers.

At t = 24, they retained 24.7 % of the answers.

\text{Percent retention} = \dfrac{\text{24.7}}{\text{73}} \times 100 \, \% = \text{33.8 \%}\\\\\text{The students retained $\large \boxed{\mathbf{33.8 \, \%}}$ of their original knowledge after two years.}

e. Maximum of the function

The maximum of the function is at t= 0.

Max = 73 %

The graph below shows your knowledge decay curve. Knowledge decays rapidly at first but slows as time goes on.

 

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3 years ago
10) Gabe put up a fence around his rectangular vegetable garden this weekend.
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Answer:

The length is 16 ft, and the width is 3 ft.

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Let L = length & let W = width.

The perimeter of a rectangle is

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A = LW

We know the perimeter and the area, so we substitute those values int he equations above and we switch sides in both equations.

Perimeter: 2(L + W) = 38

Divide both sides by 2:

L + W = 19

Area: LW = 48

We have a system of two equations in two unknowns:

L + W = 19

LW = 48

Solve the first equation for L and substitute it into the second equation.

L = 19 - W

(19 - W)W = 48

19W - W^2 - 48 = 0

Multiply both sides by -1, and rearrange the order of the terms.

W^2 - 19W + 48 = 0

(W - 16)(W - 3) = 0

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W = 16 or W = 3

Use W = 3 to find L

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A used motorcycle is on sale for 3,600
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