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4 years ago

Use the vertical line test to determine whether the relation is a function.

Mathematics

1 answer:

pentagon [3]4 years ago

5 0

Vertical line test says if you can draw a vertical line on a graph of a function and hit 2 or more points at once, it's not a function
you can see if you draw a line at x=4, you hit 3 points at once (and 3>2)
so it's not a function

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Express the angle in radian measure. 60°

Strike441 [17]

Pi radians =180 degrees:

<span>That is, π rad = 180°
</span>
60° in radian measure = 60° × π / 180°

60° × π / 180° = 1/3 π rad
= 0.33333333333π rad
= 1.0471975512 rad

7 0

3 years ago

The average of eight numbers is 56. When one of the numbers was left out, the mean decreased to 54. What number was left out?

lozanna [386]

Step-by-step explanation:

Given the average of 8 numbers = 56.

Then the Total sum of 8 numbers = 56 * 8

= 448.

Sum of 1st three numbers = 49 + 57 + 72

= 178.

So, the total = 448 - 178

= 270.

Average of the other 5 numbers = 270/5

= 54.

Verification:

178 + 270 = 448/8

= 56.

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2 years ago

$1400 being divided into some fractions! Asap!

rjkz [21]

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3 years ago

How to derive: f(w)=ln(cos(w-1))

postnew [5]

The word you're looking for is "differentiate", not "derive".

$\dfrac{\mathrm d}{\mathrm dw}\ln(\cos(w-1))=\dfrac{\frac{\mathrm d}{\mathrm dw}\cos(w-1)}{\cos(w-1)}=\dfrac{-\sin(w-1)\frac{\mathrm d}{\mathrm dw}(w-1)}{\cos(w-1)}=-\dfrac{\sin(w-1)}{\cos(w-1)}=-\tan(w-1)$

3 0

4 years ago

If f(x) = x/2 -2 and g(x) = 2x^2 + x - 3, find (f+g) (x) A. 2x^2+3/2x +1 B. 2x^2+3/2x-5 C. x^2 - 6 D. 2X^2- x/2 + 1

Fed [463]

Answer:

$\bold{(f+g)(x)=2x^2+\frac32x-5}$

Step-by-step explanation:

$f(x) =\frac x2-2\quad and\quad g(x) = 2x^2 + x - 3\\\\(f+g)(x)=f(x)+g(x)\\\\(f+g)(x)=\frac12x-2+2x^2+x-3\\\\(f+g)(x)=2x^2+\frac32x-5$

5 0

3 years ago