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MatroZZZ [7]
2 years ago
7

From the top of a 6m house, the angle of elvation to the top of a flappole is across the street is 9 degrees. the angle of depre

ssion is 22 degrees to the base of the flapole. Redraw the diagram below and label all the angles. How tall is the flagpole? Round naswer to one decimal place.

Mathematics
1 answer:
Anuta_ua [19.1K]2 years ago
5 0

The height of the flag pole which is described as in the task content is; 8.2m.

<h3>What is the height of the flagpole as described from the top of the 6m house?</h3>

The horizontal distance between the 6m house and the flagpole in discuss can be evaluated by means of the angle of depression and trigonometric identity, tan as follows;

tan 22° = 6/x

x = 6/tan 22 = 14.9m.

Consequently, the horizontal distance from the top of the house to the top of the flagpole is therefore;

tan 9° = y/14.9

y = 14.9 tan 9° = 2.2m

Ultimately, the height of the flagpole is; 6+2.2 = 8.2m.

Read more on trigonometric identities;

brainly.com/question/24349828

#SPJ1

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Can some one help me
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Answer:

5/6

Step-by-step explanation:

<em>Dividing fractions:</em>

<em>Step 1: Rewrite the first fraction as it is.</em>

<em>Step 2: Replace the division sign with a multiplication sign.</em>

<em>Step 3: Flip the second fraction.</em>

<em>Step 4: Multiply the fractions and reduce the product if necessary.</em>

Let's use the rule of dividing fractions on your problem.

Step 1: Rewrite the first fraction as it is.

\dfrac{5}{8}

Step 2: Replace the division sign with a multiplication sign.

\dfrac{5}{8} \times

Step 3: Flip the second fraction.

\dfrac{5}{8} \times \dfrac{4}{3}

Step 4: Multiply the fractions and reduce the product if necessary.

To multiply fractions, multiply the numerators together, and multiply the denominators together.

\dfrac{5}{8} \times \dfrac{4}{3} = \dfrac{5 \times 4}{8 \times 3} = \dfrac{20}{24}

We notice that the greatest common factor of 20 and 24 is 4, so we divide both the numerator and denominator by 4 to reduce the fraction.

= \dfrac{4 \times 5}{4 \times 6} = \dfrac{5}{6}

5 0
3 years ago
I don’t understand this one
Masja [62]

Answer:

  see below

Step-by-step explanation:

Put -1 where x is in each expression and evaluate it.

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You will find that the expression is zero when the numerator is zero. And you will find the numerator is zero when it has a factor that is equivalent to ...

  (x +1)

Substituting x=-1 into this factor makes it be ...

  (-1 +1) = 0

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Evaluating the first expression, we have ...

\dfrac{4(x+1)}{(4x+5)}=\dfrac{4(-1+1)}{4(-1)+5}=\dfrac{4\cdot 0}{1}=0

This first expression is one you want to "check."

You can see that the reason the expression is zero is that x+1 has a sum of zero. You can look for that same sum in the other expressions. (The tricky one is the one with the factor (x -(-1)). You know, of course, that -(-1) = +1.)

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4 years ago
find the equation of parabola when point of intersection of directrix and axis is at (0,4) and focus at (6,4) ​
Allushta [10]

Answer:

Find the coordinates of the point of intersection of the axis and the directrix of the parabola whose focus is (3,3) and directrix is 3x−4y=2. Find also the length of the latus-rectum.

Step-by-step explanation:

6 0
3 years ago
Solve the initial value problem y'=2 cos 2x/(3+2y),y(0)=−1 and determine where the solution attains its maximum value.
zloy xaker [14]

Answer:

y=\frac{-3\pm\sqrt{4sin2x+1}}{2}

x={\pi}{4}

Step-by-step explanation:

We are given that

y'=\frac{2cos2x}{3+2y}

y(0)=-1

\frac{dy}{dx}=\frac{2cos2x}{3+2y}

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Taking integration on both sides then we get

\int (3+2y)dy=2\int cos 2xdx

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Using formula

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Substitute x=0 and y=-1

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Substitute the value of C

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y=\frac{-3\pm\sqrt{(3)^2-4(1)(-sin2x+2)}}{2}

By using quadratic formula

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

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When the solution is maximum then y'=0

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2x=\frac{\pi}{2}

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3 years ago
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