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arsen [322]
2 years ago
10

The probabilities of a positive response to two government programs from citizens in eight cities are given in the table. What i

s the chance of a positive response for program 1, given that the individual is from Houston?
A. 68.8%
B. 69.7%
C. 79.4%
D. insufficient data

Mathematics
1 answer:
bearhunter [10]2 years ago
4 0

Using conditional probability, and considering that the percentage of individuals from Houston is not given, it is found that the correct option is given by:

  • D. insufficient data

<h3>Conditional Probability </h3>

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

  • P(B|A) is the probability of event B happening, given that A happened.
  • P(A \cap B) is the probability of both A and B happening.
  • P(A) is the probability of A happening.

In this problem, the events are:

  • Event A: Individual from Houston.
  • Event B: Positive response for program 1.

From Houston, 69.7% of people have positive responses for program 1, hence P(A \cap B) = 0.697.

However, to find the conditional probability, the percentage of people surveyed from Houston is needed, and this probability is not given, hence, the is insufficient data, and option D is correct.

To learn more about conditional probability, you can take a look at brainly.com/question/25908281

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Step-by-step explanation:

(x²-1)(x+1)≥0

As it has two multiples,

Therefore,

Either,

x²-1≥0

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x≤1

Or,

x+1≥0

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Find the equation of a line with each of the following characteristics. a) parallel to the line y = 3x + 5 and has a y-intercept
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y = 1/2x - 1

Step-by-step explanation:

When you put all three equations from the question into a graph and then input the equation i just gave you it will be perpendicular to line B & C, also it will be parallel to line A. Finally you can check yourself that it also has a y-intercept of (0,-1) & an x-intercept of (2,0). Hopefully this helps out & gets brainliest. xD

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1. Write the standard form of the line that passes through the given points. (7, -3) and (4, -8)
Sveta_85 [38]

Answer:

1. -5x+3y+44=0

2. 2x+y-2=0

3. 2x+y-4=0

Step-by-step explanation:

Standard form of a line is Ax+By+C=0.

If a line passing through two points then the equation of line is

y-y_1=m(x-x_1)

where, m is slope, i.e.,m=\dfrac{y_2-y_1}{x_2-x_1}.

1.

The line passes through the points (7,-3) and (4,-8). So, the equation of line is

y-(-3)=\dfrac{-8-(-3)}{4-7}(x-7)

y+3=\dfrac{-5}{-3}(x-7)

y+3=\dfrac{5}{3}(x-7)

3(y+3)=5(x-7)

3y+9=5x-35

-5x+3y+9+35=0

-5x+3y+44=0

Therefore, the required equation is -5x+3y+44=0.

2.

We need to find the equation of the line, in standard form, that has a y-intercept of 2 and is parallel to 2 x + y =-5.

Slope of the line : m=\dfrac{-\text{Coefficient of x}}{\text{Coefficient of y}}=\dfrac{-2}{1}=-2

Slope of parallel lines are equal. So, the slope of required line is -2 and it passes through the point (0,2).

Equation of line is

y-2=-2(x-0)

y-2=-2x

2x+y-2=0

Therefore, the required equation is 2x+y-2=0.

3.

We need to find the equation of the line, in standard form, that has an x-intercept of 2 and is parallel to 2x + y =-5.

From part 2, the slope of this line is -2. So, slope of required line is -2 and it passes through the point (2,0).

Equation of line is

y-0=-2(x-2)

y=-2x+4

2x+y-4=0

Therefore, the required equation is 2x+y-4=0.

5 0
2 years ago
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