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Naddika [18.5K]
2 years ago
12

Hhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhjnrby

Mathematics
1 answer:
pishuonlain [190]2 years ago
3 0

Answer:

hhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhlb

Step-by-step explanation:

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At 3:30 p.m., you have 15 megabytes of a movie. At 3:45 p.m., you have 75 megabytes. What is the download rate in megabytes per
snow_lady [41]
Because the time moved up by 15 minutes, we would already know that it would be (blank) megabytes per 15 minutes

75 megabytes - 15 megabytes = 60

this would mean 60 megabytes are downloaded per 15 minutes

simplified by 15, our answer would be 4 megabytes downloaded per minute

both of the answers above would be acceptable :)
7 0
3 years ago
What is the volume of a cube with length 7 cm? V = lwh cm3
bonufazy [111]
343 Due to the fact that it is all the same length it will just multiply to 343 7*7*7=<span>343</span>
5 0
3 years ago
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How many radians is 126
dexar [7]

Answer:

.7pi

Step-by-step explanation:

To convert from degrees to radians, multiply by pi/180

126 * pi/180

.7 pi

5 0
2 years ago
Find the domain of h(x)= 1/ 3x^2-15x
Schach [20]

Hello!

To find the domain of the function h(x), we need to find the values of x where it is undefined.

We can begin by factoring the denominator of the rational function, h(x).

h(x) = 1/(3x² - 15x) (factor 3x from the binomial)

h(x) = 1/3x(x - 5)

After factoring the denominator, apply the zero product property.

3x = 0 (divide both sides by 3)

x = 0

x - 5 = 0 (add 5 to both sides)

x = 5

The values of 0 and 5 cause h(x) to be undefined. The function h(x) comes from negative infinity to zero, where there is an asymptote. Also, from zero to five, there is also an asymptote. Finally, the function h(x) also goes to infinity from five.  

So therefore, the domain of the function h(x) is: (-∞, 0) ∪ (0, 5) ∪ (5, ∞).

8 0
2 years ago
Read 2 more answers
PLEASE HELP ME . how can the converse of the Pythagorean theorem help you determine whether the roped off area is in the shape o
trapecia [35]

Step-by-step explanation:

From the Pythagorean theorem we have:

a^2+b^2=c^2           <em>subtract b² from both sides</em>

a^2=c^2-b^2\to a=\sqrt{c^2-b^2}

Same:

b=\sqrt{c^2-a^2}

4 0
3 years ago
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