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Lelechka [254]
3 years ago
6

How much does it cost to run a computer for 50 hours in a week if the monitor runs on 140 Watts and the tower runs on 260 Watts

and the Electric Company charges 11.2 cents per kilowatt-hour?​
Mathematics
1 answer:
dangina [55]3 years ago
8 0

Answer:

Total cost will be 224 cents

Step-by-step explanation:

We have given that total time t = 50 hour

It is given that monitor ruins at 140 watts

So P = 140 watt

We know that energy = power × time

So energy required for monitor run = 140×50 = 7000 watt hour = 7 kWh

Now tower runs at a power of 260 watts

So power P = 260 watt

So energy required for tower run = 260×50 = 13 kWh

Total energy required = 13 +7 =20 kWh

It is given that company charges 11.2 cents per kilowatt hour  

So total cost = 12×11.2 = 224 cents

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motikmotik

Step-by-step explanation:

the surface area consists of 6 individual areas :

front and back (both are equal)

left and right (both are equal)

top and bottom

front and back are trapezoids.

the area of a trapezoid is

(base 1 + base 2)/2 × h

the bases are the 2 parallel sides.

in our case the area of one trapezoid is

(5 + 19)/2 × 12.1 = 145.2 ft²

front and back together then are 290.4 ft².

left and right are 8×14 rectangles:

8×14 = 112 ft²

together they are 224 ft².

the bottom is a 5×8 rectangle :

5×8 = 40 ft²

the top is a 19×8 rectangle :

19×8 = 152 ft²

so, the total surface area is

290.4 + 224 + 40 + 152 = 706.4 ft²

4 0
2 years ago
How do you do series with an n
SOVA2 [1]
The problem can be solved step by step, if we know certain basic rules of summation.  Following rules assume summation limits are identical.
\sum{a+b}=\sum{a}+\sum{b}
\sum{kx}=k\sum{x}
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\sum_{r=1}^n{r}=n(n+1)/2

Armed with the above rules, we can split up the summation into simple terms:
\sum_{r=1}^n{40r-21n+8}=n
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=20n(n+1)-21n^2+8n
=28n-n^2

=> (a) f(x)=28n-n^2
=> f'(x)=28-2n 
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4 0
3 years ago
it costs $36.75 for 3 tickets to visit the science center. it costs $51 for 4 tickets to visit the zoo. which attraction will co
lord [1]

Find the cost for one ticket for the science center.

36.75 ÷ 3 = 12.25

Multiply the product with 12 to get the cost of 12 tickets.

12.25 × 12 = 147

Find the cost of 1 zoo ticket.

51 ÷ 4 = 12.75

Find the cost of 12 tickets by multiplying the product and 12

12.75 × 12 = $153

12 Science Center Tickets cost $147

12 zoo tickets cost $153


The <u><em>Zoo</em></u> costs more than the Science Center.


To find out how much more the Zoo costed, subtract 147 from 153.

153 - 147 = 6

The zoo only costs <u><em>$6 </em></u>more for 12 students.

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5 0
3 years ago
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Find the following measure for this figure.
Svetllana [295]

Answer: first option.

Step-by-step explanation:

The formula you must use to calculate the volume of the figure shown is the following:

V=\frac{BH}{3}

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Assuming that the base of the pyramid is a square, you have that B is:

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6 0
3 years ago
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PRACTICE
Novay_Z [31]

Answer:

k = 20

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The common prime factors are 2 and 3²

HCF = 2 × 3² = 2 × 9 = 18

Thus

k - 2 = 18 ( add 2 to both sides )

k = 20

4 0
3 years ago
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