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2 years ago

8

Calculate the distance between the points C = (0,-2) and L= (-4, 1) in the coordinate plane. Give an exact answer. (not a decima

l approximation)

1 answer:

schepotkina [342]2 years ago

7 0

Answer: 5

Step-by-step explanation:

$\sqrt{(-4-0)^2 + (1-(-2))^2}=5$

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What is the quotient of 1.888\times 10^91.888×10 9 and 5.9 \times 10^65.9×10 6 expressed in scientific notation?

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Given:

The expressions are $1.888\times 10^9$ and $5.9\times 10^6$ .

To find:

The quotient of $1.888\times 10^9$ and $5.9\times 10^6$ expressed in scientific notation.

Solution:

Quotient of $1.888\times 10^9$ and $5.9\times 10^6$ is:

$\dfrac{1.888\times 10^9}{5.9\times 10^6}=\dfrac{1.888}{5.9}\times \dfrac{10^9}{10^6}$

$\dfrac{1.888\times 10^9}{5.9\times 10^6}=0.32\times 10^{9-6}$

$\dfrac{1.888\times 10^9}{5.9\times 10^6}=0.32\times 10^{3}$

In the scientific notation, the first number is between 1 to 10. So, 0.32 can be written as $\dfrac{3.2}{10}$ .

$\dfrac{1.888\times 10^9}{5.9\times 10^6}=\dfrac{3.2}{10}\times 10^{3}$

$\dfrac{1.888\times 10^9}{5.9\times 10^6}=3.2\times 10^{3-1}$

$\dfrac{1.888\times 10^9}{5.9\times 10^6}=3.2\times 10^{2}$

Therefore, the value of the quotient is $3.2\times 10^{2}$ .

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