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xenn [34]
3 years ago
15

What does the line x= 2 look like?

Mathematics
2 answers:
ArbitrLikvidat [17]3 years ago
6 0
X = 2 means for whatever y value you select the x value will be 2. So if you graph a couple of coordinates it becomes quickly evident that x = 2 is a vertical line that crosses the x axis at 2.
Svet_ta [14]3 years ago
3 0
X = 2

This would show a vertical line crossing the x axis at 2. 

Since y = 0, there is no y intercept, which means it does not cross the y axis. 


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the radius of a circle is 5 meter what is the area,in square meter,of circle? Round to the nearest tenth
Slav-nsk [51]

Answer:

78.54 rounded to the tenths it is 78.5

Step-by-step explanation:

I did the math. And I did my work like this

5*5=25

25*pi=78.5398163

Rounded to hundredths 78.54

Rounded to tenths 78.5 Hope this helps, let me know if correct, and have a great day!!

6 0
2 years ago
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The surface area of rectangular prism is 48 ft.². The area of its front is 4 ft.², and the area of one side is 10 ft.². What is
DaniilM [7]
I think the answer is 20.
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3 years ago
Simplify: –3(y + 2)2 – 5 + 6yWhat is the simplified product in standard form?
sweet-ann [11.9K]

Answer by Mimiwhatsup:

\mathrm{Multiply\:the\:numbers:}\:3\cdot \:2=6\\=-6\left(y+2\right)-5+6y\\-6\left(y+2\right)\mathrm{Apply\:the\:distributive\:law}:\quad \:a\left(b+c\right)=ab+ac\\a=-6,\:b=y,\:c=2\\=-6y+\left(-6\right)\cdot \:2\\Apply\:minus-plus\:rules\\+\left(-a\right)=-a\\=-6y-6\cdot \:2\\\mathrm{Multiply\:the\:numbers:}\:6\cdot \:2=12\\=-6y-12\\=-6y-12-5+6y\\\mathrm{Simplify}\:-6y-12-5+6y\\Group\:like\:terms\\=-6y+6y-12-5\\\mathrm{Add\:similar\:elements:}\:-6y+6y=0\\=-12-5\\

\mathrm{Subtract\:the\:numbers:}\:-12-5=-17\\Answer is: =-17

6 0
3 years ago
Which of the following represents the zeros of f(x) = 2x3 − 5x2 − 28x + 15?
likoan [24]

\mathrm{Use\:the\:rational\:root\:theorem}

a_0=15,\:\quad a_n=2

\mathrm{The\:dividers\:of\:}a_0:\quad 1,\:3,\:5,\:15,\:\quad \mathrm{The\:dividers\:of\:}a_n:\quad 1,\:2

\mathrm{Therefore,\:check\:the\:following\:rational\:numbers:\quad }\pm \frac{1,\:3,\:5,\:15}{1,\:2}

-\frac{3}{1}\mathrm{\:is\:a\:root\:of\:the\:expression,\:so\:factor\:out\:}x+3

-\frac{3}{1}\mathrm{\:is\:a\:root\:of\:the\:expression,\:so\:factor\:out\:}x+3

\mathrm{Compute\:}\frac{2x^3-5x^2-28x+15}{x+3}\mathrm{\:to\:get\:the\:rest\:of\:the\:eqution:\quad }2x^2-11x+5

=\left(x+3\right)\left(2x^2-11x+5\right)

Factor: 2x^2-11x+5

2x^2-11x+5=\left(2x^2-x\right)+\left(-10x+5\right)

=x\left(2x-1\right)-5\left(2x-1\right)

2x^3-5x^2-28x+15=\left(x+3\right)\left(x-5\right)\left(2x-1\right)

\left(x+3\right)\left(x-5\right)\left(2x-1\right)=0

\mathrm{Using\:the\:Zero\:Factor\:Principle:}

thus zeros of f(x) is

x=-3,\:x=5,\:x=\frac{1}{2}

5 0
2 years ago
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Will make brainliest if answered correctly
Komok [63]

Answer:

i think the answer is (B)

Step-by-step explanation:

The y value of a point where a vertical line intersects a graph represents an output for that input x value. If we can draw any vertical line that intersects a graph more than once, then the graph does not define a function because that x value has more than one output.

6 0
3 years ago
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