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3 years ago

-5(-2) = Need help ASAP (too lazy to actually do the work )

Mathematics

2 answers:

vesna_86 [32]3 years ago

7 0

-5(-2)=10

A negative plus a negative will always be a positive :)

just olya [345]3 years ago

4 0

I think the answer is 10

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What is the distance between (-5,8) and (-5.-8)

lisabon 2012 [21]

Answer: Use the formula y = mx + b in order to solve for b. Then, plug in known vaules.

y= -13x -57

Step-by-step explanation:

7 0

2 years ago

Find the value of x.

koban [17]

Answer:

x = 110°

Step-by-step explanation:

The Outside Angle Theorem states that the measure of the angle formed by two secants or a secant and tangent from a point outside of a circle is half the difference between the two arcs.

This means that ½ (210 – x) = 50.

½ ( 210 – x ) × 2 = 50 × 2

210 – x = 100.

210 – x + x = 100 + x.

210 = 100 + x.

100 + x = 210.

100 + x – 100 = 210 – 100.

x = 110.

This value must be true because:

½ ( 210 – 110 ) = 50.

½ ( 100 ) = 50.

50 = 50.

8 0

2 years ago

The CP of 25 articles is equal to the SP of 30 articles . Find the profit and loss percentage .

Studentka2010 [4]

Answer:

Loss = 16.67%

Step-by-step explanation:

Assume cost price(CP) of 1 article = x

Therefore cost price of 25 articles = 25x

Given cost price of 25 article = selling price of 30 articles

Clearly, it is a loss.

Selling price(SP) of 30 articles = 25x

$So , \ selling \ price\ of\ one\ article = \frac{25x}{30}\\\\Therefore , Loss \% = \frac{CP - SP}{CP} \times 100\\$

$=\frac{x - \frac{25x}{30}}{x } \times 100\\\\=\frac{30x - 25x }{30x }\times 100\\\\=\frac{5}{30} \times 100\\\\=16.67 \%$

5 0

3 years ago

Read 2 more answers

An object is launched straight into the air. The projectile motion of the object can be modeled using h(t) = 96t – 16t2, where t

ratelena [41]

Answer with Step-by-step explanation:

We are given that height of projectile after t seconds is given by

$h(t)=96t-16t^2$

a.h(t)=144 ft

$144=96t-16t^2$

$16t^2-96t+144=0$

$t^2-6t+9=0$

$t^2-3t-3t+9=0$

$t(t-3)-3(t-3)=0$

$(t-3)(t-3)=0$

t-3=0

t=3

After 3 s, the height of the project will be 144 feet in the air.

b.h(t)=0

$96t-16t^2=0$

$16t(6-t)=0$

$16t=0\implies t=0$

$6-t=0\implies t=6$

At t=0, the initial position of projectile

At t=6 s , the projectile will hit the ground.

6 0

3 years ago

Solve the system by elimination. State whether the system has one solution, infinite solutions, or no solution.

lukranit [14]

I'm not sure I'm right, I'm not all that good at elimination but I think the answer is y = 13. So I guess the answer would be A. one solution

4 0

3 years ago

Read 2 more answers