Confused on this so please help:
1 answer:
The equation p=4+3y is maximised at (4,5) and the maximised value is 31.
Given equation p=4x+3y and constraints x>0,x<4, y<5.
We have to maximise the equation p=4x+3y with constraints x>0,x<4,y<5.
To find out the points we have to make graphs of the constraints first.
From the graph we have found that points are (0,0),(0,5),(4,0),(4,5).
The above points are common points of graphs of all constraints.
The value of equations are as under:
At (0,0) , p=4*0+3*0=0
At (0,5), p=4*0+3*5=15
At (4,0),p=4*4+3*0=16
At (4,5),p=4*4+3*5=16+15=31
Maximum value of p is 31 and that is for (4,5).
Hence the equation is maximised at (4,5) and the maximum value is 31.
Learn more about equation at brainly.com/question/2972832
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Answer:
Answer Cone Z and Cylinder Y.
Step-by-step explanation:
The relationship between the volume of the cone and the volume of the cylinder with the same height and same base is the volume of the cone is 1/3 of the volume of the cylinder.
The formula for the volume of the cone is :
V = 1/3πh
The formula for the volume of the cylinder is :
V = πh
Let be the height of the cylinder Y. Therefore the height of the cone Z is 3h, when we put it into the formula we get :
V = 1/3π (3h) = π
h
Therefore Cone Z and Cylinder Y have same volume.