Confused on this so please help:
1 answer:
The equation p=4+3y is maximised at (4,5) and the maximised value is 31.
Given equation p=4x+3y and constraints x>0,x<4, y<5.
We have to maximise the equation p=4x+3y with constraints x>0,x<4,y<5.
To find out the points we have to make graphs of the constraints first.
From the graph we have found that points are (0,0),(0,5),(4,0),(4,5).
The above points are common points of graphs of all constraints.
The value of equations are as under:
At (0,0) , p=4*0+3*0=0
At (0,5), p=4*0+3*5=15
At (4,0),p=4*4+3*0=16
At (4,5),p=4*4+3*5=16+15=31
Maximum value of p is 31 and that is for (4,5).
Hence the equation is maximised at (4,5) and the maximum value is 31.
Learn more about equation at brainly.com/question/2972832
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