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3 years ago

15

A miner started at 8 feet above sea level and then traveled 23 feet straight down into a mine shaft. What was the miner's elevat

ion after traveling down the mine shaft?

1 answer:

KatRina [158]3 years ago

3 0

Answer:

-15 ft or 15 ft below sea level

Step-by-step explanation:

He started at +8 ft.

Then he went 23 ft down, that is -23 ft.

8 ft + (-23 ft) = 8 ft - 23 ft = -15 ft

Answer: -15 ft

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Answer:

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Step-by-step explanation:

We will use segment formula to find the coordinates of point that will partition our line segment PQ in a ratio 3:1.

When a point divides any segment internally in the ratio m:n, the formula is:

$[x=\frac{mx_2+nx_1}{m+n},y= \frac{my_2+ny_1}{m+n}]$

Let us substitute coordinates of point P and Q as:

$x_1=-8$ ,

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$x_2=4$

$y_2=12$

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$[x=\frac{4}{4},y=\frac{32}{4}]$

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Step-by-step explanation:

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