Please help me !! due today:(

Mathematics

1 answer:

raketka [301]1 year ago

7 0

Answer:

$\huge\boxed{\sf x = 65 \textdegree}$

Step-by-step explanation:

Using trigonometric ratio cos.

Here,

Theta = θ = x
Adjacent = 12
Hypotenuse = 28

<h3>Finding x:</h3>

$\displaystyle cos \theta =\frac{adjacent}{hypotenuse} \\\\cos \ x =\frac{12}{28} \\\\cos \ x = 0.43\\\\x = cos^{-1} 0.43\\\\x = 65 \textdegree\\\\\rule[225]{225}{2}$

You might be interested in

In stage 2 of a rocket's takeoff, the speed of the rocket increases at a rate of 4.3% per minute. The speed of the rocket at the

Sveta_85 [38]

The correct option is: B. $25000=5000(1.043)^t$

Explanation

The general form of growth equation is: $A=P(1+r)^t$ , where A = final amount, P = initial amount, r = growth rate in decimal form and t = time duration

Here, the speed of the rocket at the beginning was 5,000 kilometers per hour and at the end will be 25,000 kilometers per hour. The speed increases at a rate of 4.3% per minute.

That means, $A= 25000 , P= 5000, r= 4.3\% = 0.043$

Now plugging these values into the above equation, we will get......

$25000=5000(1+0.043)^t\\ \\ 25000=5000(1.043)^t$

So, the equation that could be used to determine the time for the speed of the rocket to reach 25,000 kilometers per hour will be: $25000=5000(1.043)^t$

8 0

3 years ago

Read 2 more answers

Divide: -84 by -7 A) -14 B) -13 C) 12 D) 13

rewona [7]

C.12

Divide
-84•/•7=12

5 0

3 years ago

Read 2 more answers

The greatest common factor of 3m^2n+12mn^2 is

FromTheMoon [43]

$3m^2n=3mn\cdot m\\\\12mn^2=3mn\cdot4n\\\\GCF(3m^2n;\ 12mn^2)=3mn\\\\3m^2n+12mn^2=3mn(m+4n)$