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andreev551 [17]
2 years ago
7

Find the area of a cylinder of radius 4 cm and height 5 cm

Mathematics
2 answers:
irakobra [83]2 years ago
7 0
<h3>✠ Given:-</h3>

  • Radius of the Cylinder = 4 cm
  • Height of the Cylinder = 5 cm

<h3>✠ To Find:-</h3>

  • Area of the Sphere = ??

<h3>✠ Solution:-</h3>

⚘ Here , we Have Given That Radius of the Sphere is 4 cm and Height of the Cylinder is 5 cm. we have to find the Area of the Cylinder , We know that formula used to find the area; <u>Area of Cylinder = 2πr²+2πrh</u>.....

☼ <u>Calculating the Area of the Cylinder</u>;

\\  \sf \implies \: Area_{ \red{ \{Cylinder \}}} \:  =  \:  \: 2 \: \pi \: r {}^{2} + 2 \: \pi \: r  \: h  \\

\\  \sf \implies \: Area_{ \red{ \{Cylinder \}}} \:  =  \bigg( \: 2 \:  \times  \: \frac{22}{7}  \:  \times \: 4{}^{2} \bigg)+ \bigg(2 \:  \times  \: \frac{22}{7}  \:  \times \: 4 \: \times   \:  5 \bigg)\\

\\  \sf \implies \: Area_{ \red{ \{Cylinder \}}} \:  =  \bigg( \: 2 \:  \times  \: \frac{22}{7}  \:  \times \: 4 \:  \times \:  4 \bigg)+ \bigg(2 \:  \times  \: \frac{22}{7}  \:  \times \: 4 \: \times   \:  5 \bigg)\\

\\  \sf \implies \: Area_{ \red{ \{Cylinder \}}} \:  =  \bigg( \: 2 \:  \times  \: \frac{22}{7}  \:  \times \: 16 \bigg)+ \bigg(2 \:  \times  \: \frac{22}{7}  \:  \times \: 20\bigg)\\

\\  \sf \implies \: Area_{ \red{ \{Cylinder \}}} \:  =  \bigg(  \: \frac{2 \times 22 \times 16}{7}\bigg)+ \bigg(  \: \frac{2 \times 22 \times 20}{7}  \bigg)\\

\\  \sf \implies \: Area_{ \red{ \{Cylinder \}}} \:  =  \bigg(  \: \frac{704}{7}\bigg)+ \bigg(  \: \frac{880}{7}  \bigg)\\

\\  \sf \implies \: Area_{ \red{ \{Cylinder \}}} \:  =  \bigg(  \: \frac{704}{7}\bigg)+ \bigg(  \: \frac{880}{7}  \bigg)\\

\\  \sf \implies \: Area_{ \red{ \{Cylinder \}}} \:  =  100.57 \:  \: +125.7  \:  \: \\

\\  \sf \implies \: Area_{ \red{ \{Cylinder \}}} \:  =  226  \:  cm\: \\

\\  \\ ✠  \:  \: { \underline{\bf { \color{blue}{ \:  \: Additional  \:  \: Information :- \:  \: }}}} \\  \\

⇥ Perimeter of rectangle = 2(length× breadth)

⇥ Diagonal of rectangle = √(length ²+breadth ²)

⇥ Area of square = side²

⇥ Perimeter of square = 4× side

⇥ Volume of cylinder = πr²h

⇥ T.S.A of cylinder = 2πrh + 2πr²

⇥ Volume of cone = ⅓ πr²h

⇥ C.S.A of cone = πrl

⇥ T.S.A of cone = πrl + πr²

⇥ Volume of cuboid = l × b × h

⇥ C.S.A of cuboid = 2(l + b)h

⇥ T.S.A of cuboid = 2(lb + bh + lh)

⇥ C.S.A of cube = 4a²

⇥ T.S.A of cube = 6a²

⇥ Volume of cube = a³

⇥ Volume of sphere = 4/3πr³

⇥ Surface area of sphere = 4πr²

⇥ Volume of hemisphere = ⅔ πr³

⇥ C.S.A of hemisphere = 2πr²

⇥ T.S.A of hemisphere = 3πr²

olga55 [171]2 years ago
4 0

Answer:

226.19cm^2

Step-by-step explanation:

Total surface area of cylinder = 2πr(r + h).

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