Im not sure if this really helps but I hope it does
10m + 80 = P
where every month he gets 10, and for 6 months, he now has 60
plus the 80 he already has
so (10 * 6 ) + 80 = 140
A) multiple the 3 x 4 and add 1.
3 x 4 = 12 + 1 = 13
13/3
B) (7 x 3) + 2 = 23/3
C) (4 x 2) + 1 = 9/2
D) (2 x 8) + 7 = 23/8
This answer is A, first you subtract 3x from both sides simplify 8x-9-3x to 5x-9, add 9 to both sides, simplify 4+9 to 13, divided both sides by 5 and you’ll get 2.6
Let the money alleli initially had be x
Money after buying clothes = x-(1/2)x=(1/2)x
Money spent on shoes = (1/2)x × (1/3)x=(1/6)x
Remaining money = x minus( (1/2)x + (1/6)x)= (1/3)x
Also we know the remaining money is 1000
Therefore
(1/3)x = 1000
Multiplying 3 on both sides
X = 3×1000
X = 3000
The initial amount she had is 3000
Hope this is right!!
