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Taya2010 [7]
4 years ago
7

Which represents the solution(s) of the graphed system of equations, y = –x2 + x + 2 and y = –x + 3?

Mathematics
2 answers:
lukranit [14]4 years ago
6 0

Answer:

option a or (1,2) on edge

Step-by-step explanation:

cupoosta [38]4 years ago
3 0

For this case we have the following system of equations:

y = -x ^ 2 + x + 2\\y = -x + 3

We observe that we have a quadratic equation and therefore the function is a parabola.

We have a linear equation.

Therefore, the solution to the system of equations will be the points of intersection of both functions.

When graphing both functions we have that the solution is given by:

x = 1\\y = 2

That is, the line cuts the quadratic function in the following ordered pair:

(x, y) = (1, 2)

Answer:

the solution (s) of the graphed system of equations are:

(x, y) = (1, 2)

See attached image.

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HELPPPP!!!!!!!!!!!!!
juin [17]
I think its C Because Aob is a given angle Boc is where we prove Aob so Im 95% sure its c
4 0
2 years ago
PLEASE HELP ME
denis23 [38]

Answer:

(1) The possible outcomes are: X = {0, 1, 2, 3}.

(2) The number of times should Hartley spin a difference of 1 is 36.

(3) The number of times should Hartley spin a difference of 0 is 24.

Step-by-step explanation:

The number of sections on the spinner is 4 labelled as {1, 2, 3, 4}.

The total number of spins for each of the spinner is, <em>n</em> = 96.

(1)

The sample space of spinning both the spinners together are:

S = {(1, 1), (1, 2), (1, 3), (1, 4)

      (2, 1), (2, 2), (2, 3), (2, 4)

      (3, 1), (3, 2), (3, 3), (3, 4)

      (4, 1), (4, 2), (4, 3), (4, 4)}

Total = 16.

The possible outcomes are:

X = {0, 1, 2, 3}.

(2)

The sample space with the difference 1 are:

S₁ = {(1, 2), (2, 1), (2, 3), (3, 2), (3, 4), (4, 3)}

n (S₁) = 6

The probability of the difference 1 is:

P(\text{Diff}=1)=\frac{n(S_{1})}{N}=\frac{6}{16}=\frac{3}{8}

The spinners were spinner 96 times.

The expected number of times would Hartley spin a difference of 1 is:

E(\text{Diff}=1)=P(\text{Diff}=1)\times n\\\\=\frac{3}{8}\times 96\\\\=36

Thus, the number of times should Hartley spin a difference of 1 is 36.

(3)

The sample space with the difference 0 are:

S₂ = {(1, 1), (2, 2), (3, 3), (4, 4)}

n (S₂) = 4

The probability of the difference 0 is:

P(\text{Diff}=0)=\frac{n(S_{2})}{N}=\frac{4}{16}=\frac{1}{4}

The spinners were spinner 96 times.

The expected number of times would Hartley spin a difference of 0 is:

E(\text{Diff}=0)=P(\text{Diff}=0)\times n\\\\=\frac{1}{4}\times 96\\\\=24

Thus, the number of times should Hartley spin a difference of 0 is 24.

4 0
3 years ago
Which expression is equivalent to 8
Marina CMI [18]

Step-by-step explanation:

-8 × -1

8 × 1

2 × 4

I hope this helps!

6 0
3 years ago
Is 4 kilograms is egual to 4000mgs
Zigmanuir [339]
No.
So, there are 1000 milligrams in one gram, making the 4000 mgs equal to 4 grams.
There are 1000 grams in one kilogram, so 4 kilograms is equal to 4000 grams.

4000 =/= 4
So, 4 kilograms and 4000 milligrams are not equal.
7 0
3 years ago
Read 2 more answers
Solve: <img src="https://tex.z-dn.net/?f=%5Cfrac%7B2x-20%7D%7B3%7D%20%3D2x" id="TexFormula1" title="\frac{2x-20}{3} =2x" alt="\f
Evgen [1.6K]

Answer:

x = - 5

Step-by-step explanation:

\frac{2x-20}{3} = 2x ( multiply both sides by 3 to clear the fraction )

2x - 20 = 6x ( subtract 2x from both sides )

- 20 = 4x ( divide both sides by 4 )

- 5 = x

7 0
3 years ago
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