Domain of f(x)=(1/4)^x

Mathematics

1 answer:

ANEK [815]2 years ago

6 0

Answer: B

Step-by-step explanation:

The domain of a function is the set of x-values.

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Three security cameras were mounted at the corners of a triangles parking lot. Camera 1 was 110 ft from camera 2, which was 137

Nata [24]

Answer:

<em>Camera 2nd has to cover the maximum angle, i.e. </em> $78.70^\circ$ .

Step-by-step explanation:

Please have a look at the triangular park represented as a triangle $\triangle ABC$ with sides

a = 110 ft

b = 158 ft

c = 137 ft

1st camera is located at point C, 2nd camera at point B and 3rd camera at point A respectively.

We can use law of cosines here, to find out the angles $\angle A, \angle B, \angle C$

As per Law of cosine:

$cos C = \dfrac{a^{2}+b^2-c^2 }{2ab}\\cos B = \dfrac{a^{2}+c^2-b^2 }{2ac}\\cos A = \dfrac{b^{2}+c^2-a^2 }{2bc}$

Putting the values of a,b and c to find out angles $\angle A, \angle B, \angle C$ .

$cos C = \dfrac{110^{2}+158^2-137^2 }{2\times 110 \times 158}\\\Rightarrow cos C = \dfrac{12100+24964-18769 }{24760}\\\Rightarrow cos C =0.526\\\Rightarrow C = 58.24^\circ$

$cos B = \dfrac{110^{2}+137^2-158^2 }{2\times 110 \times 137}\\\Rightarrow cos B = \dfrac{12100+18769 -24964}{30140}\\\Rightarrow cos B = \dfrac{5905}{30140}\\\Rightarrow cos B =0.196\\\Rightarrow B = 78.70^\circ$

$cos A = \dfrac{158^{2}+137^2-110^2 }{2\times 158 \times 137}\\\Rightarrow cos A = \dfrac{24964+18769-12100}{43292}\\\Rightarrow cos A = \dfrac{31633}{43292}\\\Rightarrow cos A = 0.731\\\Rightarrow A = 43.05^\circ$

<em>Camera 2nd has to cover the maximum angle</em>, i.e. $78.70^\circ$ .

6 0

3 years ago

The graph shows the relationship between the distance a truck can travel and the amount of gasoline used. (5,35) What is the uni

juin [17]

The unit rate is the slope

y=mx+b

m=slope

b=y intercept

equation is y=7x

slope=7

y intercept=0

slope=unit rate because if you use 5 gasoline then you go 5 times 7 miles or 35 miles

The unit rate is 7

Hope I helped :)

8 0

3 years ago

Read 2 more answers

Records show that 12% of all college students are foreign students who also smoke. It is also known that 40% of all foreign coll

Sati [7]

Answer: the percent of the students at this university are foreign = 30%

Step-by-step explanation:

Given: Probability that college students are foreign students who also smoke: P(S|F)=0.12

Probability that foreign college students smoke P(S∩F)=0.4

The probability that the students at this university are foreign :

$P(F)=\dfrac{P(S\cap F)}{P(S|F)}$ [By conditional probability formula]