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Luba_88 [7]
2 years ago
10

4. Find the solution to the equation below. please finish this problem

Mathematics
1 answer:
velikii [3]2 years ago
4 0

Answer:

w = 12

Step-by-step explanation:

We are given the equation:

\displaystyle{\dfrac{w-2}{4} = \dfrac{2w+1}{10}}

First, clear out the denominators by multiplying both sides by LCM. In this scenario, our LCM is 40. Thus, multiply both sides by 40:

\displaystyle{\dfrac{w-2}{4} \cdot 40= \dfrac{2w+1}{10} \cdot 40}

Simplify the expressions/equations:

\displaystyle{(w-2)\cdot 10= (2w+1)\cdot 4}\\\\\displaystyle{10w-20= 8w+4}

Isolate w-variable:

\displaystyle{10w-20= 8w+4}\\\\\displaystyle{10w-8w=4+20}\\\\\displaystyle{2w=24}\\\\\displaystyle{w=12}

Hence, the solution is w = 12

If you have any questions regarding my answer or explanation, do not hesitate to ask away in comment!

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a

Step-by-step explanation:

slope= rise/run

y-intercept= where the slope intersects with the y-axis

have a great day! :)

5 0
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Normal
ira [324]

Answer:

option A: 0.2357

Step-by-step explanation:

P( less than 1.76 or greater than 2.39) = P(X < 1.76) + P( X > 2.39)

P(X < 1.76) = 0.0126 (as per the excel output)

P(X < 2.39) = 0.7769

Hence P( X> 2.39) = 1- 0.7769 = 0.223

P( less than 1.76 or greater than 2.39) = P(X < 1.76) + P( X > 2.39) = 0.0126 + 0.223 = 0.2357

P( less than 1.76 or greater than 2.39) = 0.2357

8 0
3 years ago
Read 2 more answers
Solve the linear differential equation 2xy' + y = 2√x
77julia77 [94]

Answer:

Step-by-step explanation:

General form of the linear differential equation can be written as:

\frac{dy}{dx}+P(x)y=Q(x)

For this case, we can rewrite the equation as:

\frac{dy}{dx}+\frac{1}{2x}y=\frac{\sqrt{x}}{x}

Here P(x) =\frac{1}{2x}; Q(x)=\frac{\sqrt{x}}{x}

To find the solution (y(x)), we can use the integration factor method:

Fy(x)=\int Q(x)Fdx+C \rightarrow F=e^{\int P(x)dx

Then F=e^{\int \frac{1}{2x}dx}=e^{\frac{1}{2}\ln|x|\right}=\sqrt{|x|}

So, we can find:

y\sqrt{|x|}=\int \frac{\sqrt{x}\sqrt{|x|}}{x}dx+C

Suppose that x\in \double R, then \sqrt{|x|}=\sqrt{x} , and we find:

y\sqrt{x}=x+C \rightarrow y(x)=\sqrt{x}+\frac{C\sqrt{x}}{x}

To check our solution is right or not, put your y(x) back to the ODE:

y' = \frac{1}{2\sqrt{x}}-\frac{C}{2\sqrt{x^{3}}}

2xy'=\frac{x-C}{\sqrt{x}}

2xy'+y=\frac{x-C}{\sqrt{x}}+\sqrt{x}+\frac{C\sqrt{x}}{x}=2\sqrt{x}

(it means your solution is right)

3 0
2 years ago
Evaluate inverse functions <br><br> Find the following values f^-1(f(3.14)) <br> F(f(-7))
Margaret [11]

Answer:

1. 3.14

Step-by-step explanation:

If we have

f {}^{ - 1} (f(x)

That just equals

x

For example, consider function

f(x) = 2 {}^{x}

The inverse of that function is

y = 2 {}^{x}

x = 2 {}^{y}

log_{2}(x)  =  log_{2}(2 {}^{y} )

log_{2}(x)  = y

So

f {}^{ - 1} (x) =  log_{2}(x)

If we compose the function, f(x) into f^-1(x).

We get

log_{2}(2 {}^{x})  = x

That proof of that.

1. Here x=f^-1(3.14)and f(3.14) cancel out so the answer is 3.14

2. We first find f(-7) which is -12,

We then find f(-12)= 5 so the answer here is 5.

8 0
3 years ago
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