Answer:
2
Step-by-step explanation:
substitute n=1 and n=3 in the given equation
1 st term is (1)^2-1-2 = 1 -1 -2 = -2
3rd term is (3)^2-3-2 = 9-3-2=4
sum of 1st and 3rd term is -2 + 4 = 2
Your answer would be D you would add up all the days together then just put the clear days together to get 17/30 that then reduces to .57
25/45=(5∗5)/(5∗9)=5/9
5/9 is the answer.
Probability that a student will play both is 7/30
Step-by-step explanation:
Total students = 30
No. of students who play basketball = 18
Probability that a student will play basketball = 18/30
= 3/5
No. of students who play baseball = 9
Probability that a student will play baseball = 9/30
= 3/10
No. of students who play neither sport = 10
Probability that a student will play neither sport = 10/30
= 1/3
To find :
Probability that a student will play both = p(student will play both)
No.of students who play sport = 30 - 10
= 20
Out of 20 students 18 play basketball and 9 play baseball.
So, some students play both the sports.
No. of students who play both sports = 18 + 9 - 20
= 7
p(student will play both) = 7/30
Probability that a student will play both is 7/30
