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Luba_88 [7]
2 years ago
10

4. Find the solution to the equation below. please finish this problem

Mathematics
1 answer:
velikii [3]2 years ago
4 0

Answer:

w = 12

Step-by-step explanation:

We are given the equation:

\displaystyle{\dfrac{w-2}{4} = \dfrac{2w+1}{10}}

First, clear out the denominators by multiplying both sides by LCM. In this scenario, our LCM is 40. Thus, multiply both sides by 40:

\displaystyle{\dfrac{w-2}{4} \cdot 40= \dfrac{2w+1}{10} \cdot 40}

Simplify the expressions/equations:

\displaystyle{(w-2)\cdot 10= (2w+1)\cdot 4}\\\\\displaystyle{10w-20= 8w+4}

Isolate w-variable:

\displaystyle{10w-20= 8w+4}\\\\\displaystyle{10w-8w=4+20}\\\\\displaystyle{2w=24}\\\\\displaystyle{w=12}

Hence, the solution is w = 12

If you have any questions regarding my answer or explanation, do not hesitate to ask away in comment!

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Which of the following expressions represents a function? (5 points) a {(1, 2), (4, −2), (8, 3), (9, −3)} b y2 = 16 − x2 c 2x2 +
34kurt

Answer: Option "a" is the only expression that represents a function.

Step-by-step explanation:

A function f(x) = y is a "operator" that takes an input element, x, and assigns it to only one output element, y.

So, if we have that for a given value of x.

f(x) = y and f(x) = h

where y and h are different values, then this is not a function, because is assigning the input value x to two different output values.

Let's see the different options:

a) {(1, 2), (4, −2), (8, 3), (9, −3)}

This points are of the form (x, y)

We can see that each value of x is assigned to only one value of y, so this can represent a function.

b)  y^2 = 16 − x^2

Ok, suppose that x = 0, then:

y^2 = 16 - 0 = 16

then we have that y*y = 16.

So y can take two different values:

y = 4 ---> 4*4 = 16

y = -4 ---> -4*-4 = 16.

So this is not a function.

c) 2x^2 + y^2 = 5

First, we want to isolate y in one side:

y^2 = 5 - 2*x^2

Here we have a similar case to the option b, and we can use a similar argument to prove that this is not a function, so we can discard this.

d) x = 7.

Ok, this is not a relation between two variables, so this is not a function, as if x is the input value, we have only one value of x that solves the equation.

7 0
4 years ago
James completed 4 math problems in 6 minutes. At that rate, how many would he be able to complete in 1 hour?
swat32
40 problems

60÷6 is 10

10×4 is 40
8 0
3 years ago
Read 2 more answers
Which equation would have the restriction x ≠−3 on the solution?
allsm [11]

Answer:

An example can be:

f(x)=\dfrac{1}{x-3}

Step-by-step explanation:

Which equation would have the restriction x ≠−3 on the solution?

The restriction is usually applied when the function is undefined at that point, in this case x=3.

This can happen when the denominator of a fraction became 0 at x=3. This would turn the function undefined.

An example can be:

f(x)=\dfrac{1}{x-3}

7 0
3 years ago
Solve the equation by factoring: x^2 + 13x = -42<br> Show your work and check your answer.
irga5000 [103]

Answer:

x=-6, -7

Step-by-step explanation:

x^2+13x=-42

x^2+13x-(-42)=0

x^2+13x+42=0

factor out the trinomial,

find two numbers that when they multiply,

you get the third term, which is 42 in this case.

And when you add them, you get the second term, which is 13 in this case.

(x+6)(x+7)=0

zero property

x+6=0, x+7=0,

x=0-6=-6

x=0-7=-7

5 0
3 years ago
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The graph of g(x) is f(x) translated to the left 8 units and up 2 units. What is the function rule for g(x) given f(x)=x²?
dem82 [27]
<span>The graph of g(x) is f(x) translated to the left 8 units and up 2 units. Eight units left would mean that the x value is added with 3 units to the negative side. Two units up means that f(x) is moved to point 2. Therefore, the equation would be written as follows:

f(x) + 2 = x</span>² - 3

Hope this answers the question.
7 0
3 years ago
Read 2 more answers
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