All categories

3 years ago

This is hard pls help.

Mathematics

1 answer:

Ksivusya [100]3 years ago

6 0

Answer: 100, LORD OF MERCY, HOW DO YOU NOT KNOW THIS :sob: anyways if you need more help dm me on discord nishimiya#0001

You might be interested in

Write the answer in simplest form: 5/6 − 3/5 I need this ASAP pls help

RSB [31]

Answer:

the answer is 7/30 (answer is .23 repeating)

3 0

3 years ago

A company's stock begins the week with a price of $43.85 per share. THe price changes by +$2.70 each day for the first two days,

mixas84 [53]

Given:

Initial price of the stock=$43.85

Change for the first two days=+$2.70

Change for next two days=-$1.10

Last day=-$4.45

The objective is to find the price at the last day.

Let's take the price at final day as <em>x</em>.

$\begin{gathered} x=43.85+2.70+2.70-1.10-1.10-4.45 \\ x=42.6 \end{gathered}$

Hence, the price of the stock at the last day is $42.6

5 0

1 year ago

What number divided by 3 give me five

bearhunter [10]

It is 15 because 5 times 3 is 15

7 0

3 years ago

Can someone please help me . I’ll mark brainless

Amiraneli [1.4K]

Answer:

answer for a,b and c are all zero (0).

reasons for all:

zero(0) divided by any number is zero(0).

5 0

3 years ago

If log2 5 = k, determine an expression for log32 5 in terms of k.

lukranit [14]

Answer:

$log_3_2(5)=\frac{1}{5} k$

Step-by-step explanation:

Let's start by using change of base property:

$log_b(x)=\frac{log_a(x)}{log_a(b)}$

So, for $log_2(5)$

$log_2(5)=k=\frac{log(5)}{log(2)}\hspace{10}(1)$

Now, using change of base for $log_3_2(5)$

$log_3_2(5)=\frac{log(5)}{log(32)}$

You can express $32$ as:

$2^5$

Using reduction of power property:

$log_z(x^y)=ylog_z(x)$

$log(32)=log(2^5)=5log(2)$

Therefore:

$log_3_2(5)=\frac{log(5)}{5*log(2)}=\frac{1}{5} \frac{log(5)}{log(2)}\hspace{10}(2)$

As you can see the only difference between (1) and (2) is the coefficient $\frac{1}{5}$ :

So:

$\frac{log(5)}{log(2)} =k\\$

$log_3_2(5)=\frac{1}{5} \frac{log(5)}{log(2)} =\frac{1}{5} k$

6 0

3 years ago