All categories

2 years ago

In the context of data models, relationships among records in a hierarchical model are called _____.

1 answer:

6 0

In the context of data models, relationships among records in a hierarchical model are called Branches. This is further explained below.

<h3>What are data models,?</h3>

Generally, The act of generating a visual representation of either a whole information system or portions of it in order to express the linkages between different data points and structures is known as data modeling.

In conclusion, When discussing data models, the connections between different records in a hierarchical structure are referred to as "Branches."

You might be interested in

Here is Kwame’s work writing the expression 4-2(x + 5) using fewer terms.

LenKa [72]

Answer: 20 -2x

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

A jewelry maker had 250 pieces of jewelry to sell at a local festival. she ended up selling 42% of the pieces she had made . How

Rufina [12.5K]

Answer:

<em>105 pieces of jewlery </em>

Step-by-step explanation:

42%=0.42

then 0.42*250=105

4 0

3 years ago

Read 2 more answers

If g (x) = StartFraction x + 1 Over x minus 2 EndFraction and h(x) = 4 – x, what is the value of (g circle h) (negative 3)? Eigh

brilliants [131]

Answer:

Step-by-step explanation:

Given g (x) = $\frac{x+1}{x-2}$ and $h(x) = 4-x$ , we are to find $(goh)(-3)$

First we need to get $(goh)(x)$

$(goh)(x) = g(h(x))\\g(h(x))= g(4-x)\\g(4-x) = \frac{(4-x)+1}{(4-x)-2}\\ g(4-x) = \frac{5-x}{2-x}\\substitute \ x = -3 \ into \ resulting \ function\\ g(4-x) = \frac{5-x}{2-x}\\(goh)(-3) = \frac{5-(-3)}{2-(-3)}\\\\(goh)(-3) = \frac{8}{5}\\$

Hence $(goh)(x)\ is \ Eight-fifths$

Also given f(x) = x and g(x) = 1/x, we are to find $(fog)(x)$

$(fog)(x) = f(g(x))\\f(g(x)) = f(\frac{1}{x} )\\ since \ f(x) = x^2, we\ will \ repalce\ x \ with \ \frac{1}{x} \ to \ have;\\ f(\frac{1}{x} ) =( \frac{1}{x})^2\\\\$

$f(\frac{1}{x} ) = \frac{1}{x^2}$

For the pair of function f(x) = 2/x and g(x) = 2/x

f(g(x)) = f(2/x)

f(2/x) = 2/(2/x)

f(2/x) = 2*x/2

f(2/x) = x

Hence f(g(x)) = x

For the pair of function f(x) = x-2/3 and g(x) = 2-3x

f(g(x)) = f(2-3x)

f(2-3x) = (2-3x-2)/3

f(2-3x) = -3x/3

f(2-3x) = -x

f(g(x)) = -x for the pair of function

For the pair of function f(x) = x/2 - 2 and g(x) = x/2 + 2

f(g(x)) = f(x/2 + 2)

f(x/2 + 2) = f((x+4)/2)

f((x+4)/2) = [(x+4)/2]/2 - 2

f((x+4)/2) = (x+4)/4 - 2

find the LCM

f((x+4)/2) = [(x+4)-8]/4

f((x+4)/2) = (x-4)/4

Hence f(g(x)) for the pair of function is (x-4)/4

8 0

3 years ago

If joe had 3 coins and lost 1 coin. How many coins does joe have now ?

Arte-miy333 [17]

Answer:

Step-by-step explanation:3-1

7 0

3 years ago

Read 2 more answers

Estimate square root 250 to two decimal points

Juli2301 [7.4K]

OK, the square root of 250 is 15.811 . . .
but since this can't be expressed as a decimal for your purposes, let's try factoring. Since 250 ends in a zero, only numbers 5 or 0 or those ending in 5 or 0 could be factors.
The square root of 250 can be factored into the square root of 25 and the square root of 10.
The square root of 25 is exactly 5, and the exact square root of 10 is another decimal, so your simplified answer can be expressed as 5 times the square root of 10.

3 0

3 years ago

Read 2 more answers