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ANEK [815]
3 years ago
6

Tan 15°+ Cot 15° =4​

Mathematics
2 answers:
erik [133]3 years ago
5 0
Where’s the rest of the question? Am I supposed to solve this completely?
sp2606 [1]3 years ago
4 0

Answer:

tan 15 + cot 15

= sin 15 / cos 15 + cos 15 / sin 15

= (sin²15 + cos²15) / (sin 15 cos 15)

= 1 / (1/2 sin 30)

= 2 / sin 30

= 2 / (1/2)

= 4

Step-by-step explanation:

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zloy xaker [14]
I think its 6000 am not sure am just sayin bruh 
6 0
2 years ago
When factored completely, which is a factor of 3x3 − 9x2 − 12x?
Annette [7]

Answer: I believe it’s D

Step-by-step explanation:

4 0
2 years ago
Please solve 4x-9=k for x
Lelechka [254]

Answer:

x= <u>k+9</u>

      4

Step-by-step explanation:

4x-9=k

add nine to each side

4x=k+9

divide each side by 4

x=<u>k+9</u>

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3 0
3 years ago
PLs help asap :( i have no idea how to do sigma notation
MAVERICK [17]

The correct answer is C

Sigma Notation is when we take all of the whole numbers between the starting point (which can be found as the number under the sigma sign) and the end number (which can be found above the sigma sign). Therefore, we will add together all of the values of 3k + 2 for when k is equal to all of the numbers between 2 and 7. So, let's evaluate each one first.

When k = 2

3(2) + 2 = 8

When k = 3

3(3) + 2 = 11

When k = 4

3(4) + 2 = 14

When k = 5

3(5) + 2 = 17

When k = 6

3(6) + 2 = 20

When k = 7

3(7) + 2 = 23

So we know we have the following.

8 + 11 + 14 + 17 + 20 + 23

Now for the number after the comma, we are just looking for the answer of them all added together. So the final answer should be

8 + 11 + 14 + 17 + 20 + 23, 93

7 0
2 years ago
Urgent help algebra 2 quick please
olga55 [171]

Answer: y = -3/2x + 6, y intercept is (0, 6)

Step-by-step explanation: You are dividing 2 from both -3x and 12. -3/2x cannot be simplified any further unless it's a decimal, so we leave it as -3/2x. But, since the equation was y = -3x+12 originally, we divide 12 from 2 as well and not just from 3x, and we get 6.

Hope this helped.

6 0
1 year ago
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