Yeah I’ll get right on that.
Answer:
(e) csc x − cot x − ln(1 + cos x) + C
(c) 0
Step-by-step explanation:
(e) ∫ (1 + sin x) / (1 + cos x) dx
Split the integral.
∫ 1 / (1 + cos x) dx + ∫ sin x / (1 + cos x) dx
Multiply top and bottom of first integral by the conjugate, 1 − cos x.
∫ (1 − cos x) / (1 − cos²x) dx + ∫ sin x / (1 + cos x) dx
Pythagorean identity.
∫ (1 − cos x) / (sin²x) dx + ∫ sin x / (1 + cos x) dx
Divide.
∫ (csc²x − cot x csc x) dx + ∫ sin x / (1 + cos x) dx
Integrate.
csc x − cot x − ln(1 + cos x) + C
(c) ∫₋₇⁷ erf(x) dx
= ∫₋₇⁰ erf(x) dx + ∫₀⁷ erf(x) dx
The error function is odd (erf(-x) = -erf(x)), so:
= -∫₀⁷ erf(x) dx + ∫₀⁷ erf(x) dx
= 0
Answer:
13.228 pounds
Step-by-step explanation:
Formula:
for an approximate result, multiply the mass value by 2.205
Answer:
wow
Step-by-step explanation:
lol idle b Betsey e wet get hectic
Answer:
no of kernels pop = 4.34
Step-by-step explanation:
given data
kernels pop in 5 second = 12
kernels are present = 235
solution
we get here kernels are pop at rate of here
kernels are pop at rate = 12 ÷ 235
kernels are pop at rate = 0.051063
and
we get here maximum kernels are remaining that is
maximum kernels remaining = 235 - 140
maximum kernels remaining = 85
so
no of kernels pop in 5 second will be
no of kernels pop = 0.051063 × 85
no of kernels pop = 4.34
