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vladimir1956 [14]
3 years ago
14

I need help his to do it

Mathematics
2 answers:
horsena [70]3 years ago
6 0
Sorry but it's unclear
11111nata11111 [884]3 years ago
3 0
The answer is 150 cm²
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(30pts) Solve for x:
Neporo4naja [7]

Answer:

x=12

Step-by-step explanation:

The two angles are equal to 180 degrees, we already know that one angle is 110, so we find the difference.

180-110=70

4x+22=70

70-22=48

48/4=12

4 0
3 years ago
Read 2 more answers
Could someone please help me asap!! Pleasseeeee and thanks.
kherson [118]

Answer:

Step-by-step explanation:

a² - b² = (a + b) (a - b)

1)x² - 36 = x² - 6² = (x + 6)(x-6)

2) 4x² - 16 = 4x² - 4*4 = 4(x² - 4)

                = 4(x² -2²)

                = 4(x + 4)(x-4)

3) 9x² -1 = 3²x² - 1² = (3x)² - 1²

             =(3x + 1)(3x - 1)

8 0
3 years ago
Help! Construct the circle that circumscribes DEF. Use a straightedge and a compass.
mojhsa [17]

GeoGebra is a website that allows you to use tools online. Check it out

3 0
3 years ago
If the graph of the function f has a multiple zero at x = 2, what is a possible exponent of the factor x - 2? Justify your reaso
melomori [17]

Answer:

(x-2)^2

The exponent is 2.

Step-by-step explanation:

Remember multiplicity rules:

  • If a factor has an odd multiplicity (e.g. it is raised to 1, 3, 5...) then it will cross the x-axis.
  • If a factor has an even multiplicity (e.g. it is raised to 2, 4, 6...) then it will bounce off the x-axis.

At x=2, we have the factor (x-2).

From the graph, we can see that the graph bounces off at that point.

Hence, the multiplicity of (x-2) must be even.

Therefore, a possible exponent for the factor (x-2) is 2. Any even number will suffice.

6 0
2 years ago
Find the kissing lengths of the sides of the triangle.
alina1380 [7]

Answer: The last option.

Step-by-step explanation:

The triangle shown in the figure attached is a right triangle.

1. You can calculate the lenght <em>a </em>as following:

sin\alpha=\frac{opposite}{hypotenuse}

opposite=a\\hypotenuse=6in\\\alpha=30\°

Substitute values and solve for <em>a</em>. Then, you obtain:

sin(30\°)=\frac{a}{6in}\\a=6in*sin(30\°)\\a=3in

2.  You can calculate the lenght<em> b </em>as following:

cos\alpha=\frac{adjacent}{hypotenuse}

adjacent=b\\hypotenuse=6in\\\alpha=30\°

Substitute values and solve for <em>b</em>. Then, you obtain:

cos(30\°)=\frac{b}{6in}\\b=6in*cos(30\°)

b=3\sqrt{3}in

3 0
3 years ago
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