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vodka [1.7K]
2 years ago
5

+++++

Mathematics
2 answers:
katrin2010 [14]2 years ago
6 0
Gl btc was the only reason why you don’t have
Strike441 [17]2 years ago
4 0

Step-by-step explanation:

++++5

+++++++_2

1=false

true

false

false

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How do you solve this problem in the photo?
Klio2033 [76]

Answer: 5^2

Step-by-step explanation:

Since the base are all the same, you will add the exponents and let the exponents stay the same.

5^3  * 5^4= 5^7 * 5^-5= 5^2

6 0
3 years ago
Read 2 more answers
In the expression (44 ÷ 4 + 10) - 20 , with which operation should we start?
Luden [163]
You have to do whats in the parentheses from left to right then subtract the answer you get by 20



(9x10) - (30+30)
90 - 60 = 30



8 x (12+5) -7^2
17
17-49
18 x -32

= -576.



You have to use pemdas for your check off
P=parentheses
E=exponet
M=multiplication
D=division
A=add
S=subtrabt

HOPE IM CORRECT
4 0
3 years ago
Read 2 more answers
Consider the functions f(x) = 12^x and g(x)= -2(12)^x. Which transformations must be applied to function F to produce the graph
maksim [4K]

Answer:

Step-by-step explanation:

g(x) = -2f(x)

Vertical stretch                       by virtue of the factor 2

Reflection over the x-axis      by virtue of the factor -1

5 0
2 years ago
I need help with part b. I feel like there’s a catch, I want to do the first derivative test, however, I feel like there is a be
Sladkaya [172]

Answer:

The fifth degree Taylor polynomial of g(x) is increasing around x=-1

Step-by-step explanation:

Yes, you can do the derivative of the fifth degree Taylor polynomial, but notice that its derivative evaluated at x =-1 will give zero for all its terms except for the one of first order, so the calculation becomes simple:

P_5(x)=g(-1)+g'(-1)\,(x+1)+g"(-1)\, \frac{(x+1)^2}{2!} +g^{(3)}(-1)\, \frac{(x+1)^3}{3!} + g^{(4)}(-1)\, \frac{(x+1)^4}{4!} +g^{(5)}(-1)\, \frac{(x+1)^5}{5!}

and when you do its derivative:

1) the constant term renders zero,

2) the following term (term of order 1, the linear term) renders: g'(-1)\,(1) since the derivative of (x+1) is one,

3) all other terms will keep at least one factor (x+1) in their derivative, and this evaluated at x = -1 will render zero

Therefore, the only term that would give you something different from zero once evaluated at x = -1 is the derivative of that linear term. and that only non-zero term is: g'(-1)= 7 as per the information given. Therefore, the function has derivative larger than zero, then it is increasing in the vicinity of x = -1

6 0
3 years ago
there are 2 ones, 1 five,3tens, and 1 twenty. if there are 28 bills in her wallet, what would you predict is the approximate val
Kruka [31]
There would be 8 ones, 4 fives, 12 tens, and 4 twenties. That together would be about $228
4 0
4 years ago
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