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yanalaym [24]
3 years ago
13

A boy wants to jump onto a carousel that is spinning at a rate of 14 revolutions per minute. If the carousel is 23 feet in diamt

er, how fast must the boy run to match the speed of the carousel and jump on?A) 2.68 feet per second.B) 1,011.59 feet per second.C) 33.72 feet per second.D) 16.86 feet per second.
Mathematics
1 answer:
nirvana33 [79]3 years ago
6 0

Answer:

16.86 ft/s

Step-by-step explanation:

Given that

Speed of the carousel, s = 14 rpm

Distance from the carousel, d = 23 ft

To start with, we convert the given speed to revolution per second, so that

s = 14/60 rev/sec

To find the needed speed, we use the formula

v =2πnR, remember that Diameter = 2R, so we substitute D for 2R and get πnD

v = πnD, and we use this to find our needed velocity

v = 3.142 * 14/60 * 23

v = 72.266 * 14/60

v = 16.86 ft/s

Therefore the boy must run at a speed of 16.86 ft/s in order to be able to match the carousel and jump on it

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Step-by-step explanation:

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2 years ago
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The figure below is made out of rectangles what is the perimeter of the figure below note that not all the side links are labele
Vladimir [108]

Answer:

Perimeter of the figure = 24 m.

Step-by-step explanation:

The given figure is a square of side 6 m in which a rectangle of length 4 m and width 2 m is cut at the corner.

Therefore, the missing sides are 6-4 = 2 m and 6-2 = 4 m.

Hence, the perimeter of the figure = 6 + 6 + 2 + 2 + 4 + 4 = 24 m.

3 0
3 years ago
Can somebody help me please! And explain I appreciate it!!!
True [87]

Answer:

54 beads

Step-by-step explanation:

1 hexagon = 6

2 hexagons = 10

3 hexagons = 14

Based on the pattern shown above +4 you can create an equation from this to help support finding the amount.

y = 4x + 6

y - total amount

4x - amount that is added by

6 - initial amount for 1 hexagon

Based on this you plug in 12 into x and you will find the answer:

y = 4(12) + 6

= 48 + 6

= 54

If you need to check the work honestly drawing it out, but this equation can also be supported based on the 3rd diagram of hexagon, where the initial is 6 and then 4 are added each time afterwards!!!

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0 (tens place)

0 (ones place)

2 in 200 would be the hundreds place.

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3 years ago
Calcula y comprueba las ecuaciones: plisss lo necesito alguien me puede ayudar a) 2X = 6 b) 10 + Z = 20 c) P + 9 = 11 d) 3X + 8
vesna_86 [32]

Answer:

a) x=3

b) z=10

c) P= 2

d) X=7

e) U=1

Step-by-step explanation:

Resolver una ecuación consiste en hallar los valores de la variable que hacen cierta la igualdad.

a) 2x= 6

El coeficiente es el número junto a la variable. En este caso, el coeficiente es 2. Para eliminar este número en la expresión 2x, debido a que la variable x esta multiplicada por 2, deberás dividir ambos lados de la ecuación entre 2, debido a que la operación opuesta de la multiplicación es la división.

(2x)÷2=6÷2

x= 3

Comprobar la solución de una ecuación se hace al remplazar la variable en una ecuación con el valor de la solución. La solución debería satisfacer la ecuación cuando se ingresa en esta.

En este caso:

2*3= 6

6=6

b) 10 + z= 20

En este caso se debe sumar o restar la constante que se encuentra acompañando a la variable en ambos lados de la ecuación de manera de aislar el término de la variable. En este caso:

10 - 10 + z= 20 -10

z= 10

Comprobación:

10 + z=20

10 + 10=20

20=20

c) P + 9= 11

P +9 - 9= 11 -9

P=2

Comprobación:

2 + 9= 11

11=11

d) 3X + 8 = 29

En este caso, se suma o resta la constante en ambos lados de la ecuación y luego se elimina el coeficiente de la variable mediante la división o multiplicación. Esto es:

3X + 8 - 8= 29 - 8

3X= 21

3X ÷3= 21÷3

X=7

Comprobación:

3*7 + 8=29

21+8=29

29=29

e) 2U + 8= 10

2U + 8 - 8= 10 -8

2U= 2

2U ÷2= 2÷2

U=1

Comprobación:

2*1 + 8= 10

2 + 8= 10

10=10

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