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3 years ago

Maya's cat weighs 13 lbs. 7 oz. about what is that weight in kilograms

Mathematics

2 answers:

Whitepunk [10]3 years ago

6 0

The answer in kilograms is 6.095

fredd [130]3 years ago

3 0

The unwires is 6.0951 kg

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You are selling a mobile app for $10 per user per month.if you get 7 users every month starting with 10 in the first month.how m

Ahat [919]

Selling price of app per user = $10 per month

Total no. of user in first month = 10

To tal no. of user added per month = 7

We have to find how much money is earned in one year

So the formula is n/2 * (2a +(n-1)d)

Here we have n = 12 which is total no. of months

a = 100 , which is money earned in one month

d = 70 , which is increase in money earned per month

So money earned in a year comes out to be 5820

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2 years ago

Challenge #1

o-na [289]

Answer:

Translate 10 units right, 9 units up

Step-by-step explanation:

translations simply take the image and move it up or down or side to side, reflections flip the image, dilation changes the dimensions of an image, and rotation rotates an image on its origin point.

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2 years ago

Shaded areas <br>please help guys ❤❤❤

pentagon [3]

Answer:

77cm

Step-by-step explanation:

Area of a rectangle=L×B

7×11=77cm

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2 years ago

Read 2 more answers

Mr. Smith had 34 of a peach pie left over. He split the leftover pie among his 3 co-workers.

viktelen [127]

Answer:

11.333 infinity

Step-by-step explanation:

when you divide 34 by 3 you then get 11.3 infinity which would also be a repeating decimal

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2 years ago

Can someone help me find the equivalent expressions to the picture below? I’m having trouble

miss Akunina [59]

Answer:

Options (1), (2), (3) and (7)

Step-by-step explanation:

Given expression is $\frac{\sqrt[3]{8^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}$ .

Now we will solve this expression with the help of law of exponents.

$\frac{\sqrt[3]{8^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}=\frac{\sqrt[3]{(2^3)^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}$

$=\frac{\sqrt[3]{2\times 3} }{3\times2^{\frac{1}{9}}}$

$=\frac{2^{\frac{1}{3}}\times 3^{\frac{1}{3}}}{3\times 2^{\frac{1}{9}}}$

$=2^{\frac{1}{3}}\times 3^{\frac{1}{3}}\times 2^{-\frac{1}{9}}\times 3^{-1}$

$=2^{\frac{1}{3}-\frac{1}{9}}\times 3^{\frac{1}{3}-1}$

$=2^{\frac{3-1}{9}}\times 3^{\frac{1-3}{3}}$

$=2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }$ [Option 2]

$2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(\sqrt[9]{2})^2\times (\sqrt[3]{\frac{1}{3} } )^2$ [Option 1]

$2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(\sqrt[9]{2})^2\times (\sqrt[3]{\frac{1}{3} } )^2$

$=(2^2)^{\frac{1}{9}}\times (3^2)^{-\frac{1}{3} }$

$=\sqrt[9]{4}\times \sqrt[3]{\frac{1}{9} }$ [Option 3]

$2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(2^2)^{\frac{1}{9}}\times (3^{-2})^{\frac{1}{3} }$

$=\sqrt[9]{2^2}\times \sqrt[3]{3^{-2}}$ [Option 7]

Therefore, Options (1), (2), (3) and (7) are the correct options.

6 0

2 years ago