HELP

Jeff is studying abroad in Sussex England this summer. He wants to visit a local museum outside of town this weekend. A taxi cab

Vesnalui [34]

Answer:

if it's less than 7.66km use Royal, if more than 7.66 use Queen's

Step-by-step explanation:

To get the answer you can set up mutliple equations

For Queen's Cab Company

2.70 + 0.20x = ?

for Royal Cab Company

1.55 + 0.35x = ?

Since you didn't give a distance which is what will determine which is cheaper we can solve as a set of equations.

2.70 + 0.20x = 1.55 + 0.35x

1.15 = .15x

x = 7.66

So this lets you know that at 7.66 km Royal cab company becomes more expensive due to their pence per km.

So if it's less than 7.66km use Royal, if more use Queen's

5 0

3 years ago

Help please I beg you!

adelina 88 [10]

I think the answer is angle EBF but i can't read the letters correctly to be sure
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7 0

3 years ago

Equivalent expression to −5.55−8.55c+4.35c

Y_Kistochka [10]

-5.55-8.55c+4.35c 2nd and 3rd term is like term we can connect. -digit have to larger number than +digit so the sign will be negative
-5.55-4.2c there is no like term to connect
Hence this is the answer

5 0

2 years ago

A piece of copper wire of length 200 m has a diameter of 1.2 mm.

vova2212 [387]

The volume of the copper wire is 226.080 cm³ and the mass of the wire is 2,012.112 g/cm³.

Given that, the length of copper wire=200 m=200000 mm and the diameter of the copper wire=1.2 mm.

We need to find the volume of the copper wire.

<h3>What is the formula to find the volume of the cylinder?</h3>

The formula to find the volume of a cylinder is πr²h.

Now, the volume of the copper wire=πr²h= $\frac{22}{7} \times (0.6)^{2} \times 200000=2,26,080$ mm³=226.080 cm³

If the density of copper is 8.9 g/cm³, find the mass of the wire.

We know that $Density=\frac{Mass}{Volume} }$ .

⇒8.9 g/cm³= $\frac{Mass}{226.080}$

⇒Mass=2,012.112 g/cm³

Therefore, the volume of the copper wire is 226.080 cm³ and the mass of the wire is 2,012.112 g/cm³.

To learn more about the volume of the cylinder visit:

brainly.com/question/16134180.

#SPJ1

6 0

2 years ago

Find all the values of x in the set of complex numbers that satisfy the following equation:

Fynjy0 [20]

Compute all the component integrals first:

$I_1=\displaystyle\int_0^{\pi/4}2\sec x\,\mathrm dx=2\ln(\sqrt2+1)$
$I_2=\displaystyle\int_0^2\ln x\,\mathrm dx=2(\ln2-1)$
$I_3=\displaystyle\lim_{a\to\infty}\int_{-a}^a\frac{\mathrm dx}{x^2+1}=\pi$

Now,

$\sqrt2\approx1.4\implies \sqrt2+1\approx2.4$
$\implies \left\lceil I_1\right\rceil=2$

$e$
$\implies\left\lfloor I_2\right\rfloor=-1$

$\pi\approx3.14\implies\left\lceil I_3\right\rceil=4$

So the given equation reduces to

$\displaystyle\sum_{k=-1}^2\frac{\mathrm d}{\mathrm dx}x^{k+2}=1-4!$
$\dfrac{\mathrm dx}{\mathrm dx}+\dfrac{\mathrm dx^2}{\mathrm dx}+\dfrac{\mathrm dx^3}{\mathrm dx}+\dfrac{\mathrm dx^4}{\mathrm dx}=-23$
$4x^3+3x^2+2x+24=0$

a fairly standard cubic. Incidentally, when $x=-2$ , the LHS reduces to 0, so $x+2$ is a factor of the cubic. You can find the remaining two solutions easily with the quadratic formula.

5 0

3 years ago