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2 years ago

the point of M ( a, 4 ) is the midpoint of the line segment with endpoint at A(1,3) and B(5,b). Find the value of a and b

Mathematics

2 answers:

vazorg [7]2 years ago

6 0

The value of a and b from the coordinates are 3 and 5 respectively

<h3>Midpoint of coordinates</h3>

The formula for finding the midpoint of two coordinates is expressed as;

M(x, y) = {x1+x2/2, y1+y1/2}

Given the following coordinates

M(a, 4)

A(1,3)

B(5,b)

Using the formula

a = 1+5/2

a = 6/2

a = 3

Similarly

4 = 3+b/2

8 = 3+b

b = 8-3

b = 5

Hence the value of a and b from the coordinates are 3 and 5 respectively

Learn more on midpoint here: brainly.com/question/18315903

#SPJ1

solniwko [45]2 years ago

6 0

The values are A = 3 and B = 5

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which of the functions have a range of real numbers greater than or equal to 1 or less than or equal to-1

lilavasa [31]

The question is incomplete. Here is the complete question:

Which of the functions have a range of all real numbers greater than or equal to 1 or less than or equal to -1? check all that apply.

A. $y=\sec x$

B. $y= \tan x$

C. $y= \cot x$

D. $y= \csc x$

Answer:

A. $y=\sec x$

D. $y=\csc x$

Step-by-step explanation:

Given:

The range is greater than or equal to 1 or less than or equal to -1.

The given choices are:

Choice A: $y=\sec x$

We know that, the $\sec x=\frac{1}{\cos x}$

The range of $\cos x$ is from -1 to 1 given as [-1, 1]. So,

$|\cos x|\leq 1\\\textrm{Taking reciprocal, the inequality sign changes}\\\frac{1}{|\cos x|}\geq 1\\|\sec x|\geq 1$

Therefore, on removing the absolute sign, we rewrite the secant function as:

$\sec x\leq -1\ or\ \sec x\geq 1\\$

Therefore, the range of $y=\sec x$ is all real numbers greater than or equal to 1 or less than or equal to-1.

Choice B: $y= \tan x$

We know that, the range of tangent function is all real numbers. So, choice B is incorrect.

Choice C: $y= \cot x$

We know that, the range of cotangent function is all real numbers. So, choice C is incorrect.

Choice D: $y=\csc x$

We know that, the $\csc x=\frac{1}{\sin x}$

The range of $\sin x$ is from -1 to 1 given as [-1, 1]. So,

$|\sin x|\leq 1\\\textrm{Taking reciprocal, the inequality sign changes}\\\frac{1}{|\sin x|}\geq 1\\|\csc x|\geq 1$

Therefore, on removing the absolute sign, we rewrite the cosecant function as:

$\csc x\leq -1\ or\ \csc x\geq 1\\$

Therefore, the range of $y=\csc x$ is all real numbers greater than or equal to 1 or less than or equal to-1.

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3 years ago

The circumference of a circle is

pantera1 [17]

Answer:

Step-by-step explanation:

the formula for circumference of a circle is 2 x pi x r(radius).

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3 years ago

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Please help me with geometry i really need help

Debora [2.8K]

The ratio is 1:2 meaning you would divide the 4320 by 2 to get the smaller prisim.
4320 ÷ 2 = 2160 cm^3

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3 years ago

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Lines a and b are parallel.

VashaNatasha [74]

I have added a screenshot with the complete question along with a diagram representing the scenario.

Answer:
s = 22°

Explanation:
1- getting the top right angle of line B:
We are given that:
the top right angle of line A = 158°
Since lines A and B are parallel, therefore, the top right angle of line A and the top right angle of line B are corresponding angles which means that they are equal
This means that:
Top right angle of line B = 158°

2- getting the value of s:
Now, taking a look at line B, we can note that:
angle s and the top right angle form a straight angle. This means that the sum of these two angles is 180°
Therefore:
180 = s + 158
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Hope this helps :)

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3 years ago

I don’t like to beg but I guess I’m in need..

djverab [1.8K]

Answer:

-4 < n ≤ 5

Step-by-step explanation:

Since the left inequality is an open circle and going to the right, the sign will be >

Since the right inequality sign is a closed circle and is going left, the sign would be ≤

The open circle ends at -4 so, n > -4

The closed circle ends at 5 so, n ≤ 5

You combine them and it looks like this:

-4 < n ≤ 5

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3 years ago