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o-na [289]
2 years ago
10

Consider the dot plot below. Of the following statements, which two characteristics of this dot plot make the median a better ch

oice than the mean to summarize the center of the distribution?
A dot plot with an axis marked from 0 to 10 at increments of 1 is shown. Plot shows 8 dots at 10, 7 dots at 9, 6 dots at 8, 3 dots at 7, 2 dots at 0 and 6, and 1 dot at 5.


The mean is equal to the median and the data are symmetric.

The peak is equal to the median and the data are skewed.

The data are symmetric and there are outliers.

The data are skewed and there are outliers.
Mathematics
1 answer:
hammer [34]2 years ago
6 0

The two characteristics that makes the median a better choice are: A. The data are skewed and there are outliers.

<h3>What Characteristics of a Dot Plot Makes Median a Better Choice?</h3>

In a data distribution, the median is a better choice to use to describe the data over the mean when an outlier exist and the data is skewed.

IN the dot plot given below, the data has an outlier of 10 while the data distribution is also screwed, this makes the median a better choice.

Therefore, the answer is: A. The data are skewed and there are outliers.

Learn more about the median on:

brainly.com/question/16800683

#SPJ1

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normally distributed with mean 24.6 seconds and standard deviation 0.64 seconds;the lower finishing time, the better. If the qua
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Answer:

z=1.04

And if we solve for a we got

a=24.6 +1.04*0.64=25.27

So the value of height that separates the bottom 85% of data from the top 15% is 25.27.  

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the finishing time of a population, and for this case we know the distribution for X is given by:

X \sim N(24.6,0.64)  

Where \mu=24.6 and \sigma=0.64

Solution to the problem

For this part we want to find a value a, such that we satisfy this condition:

P(X>a)=0.15   (a)

P(X   (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.  

As we can see on the figure attached the z value that satisfy the condition with 0.85 of the area on the left and 0.15 of the area on the right it's z=1.04. On this case P(Z<1.04)=0.85 and P(z>1.04)=0.15

If we use condition (b) from previous we have this:

P(X  

P(z

But we know which value of z satisfy the previous equation so then we can do this:

z=1.04

And if we solve for a we got

a=24.6 +1.04*0.64=25.27

So the value of height that separates the bottom 85% of data from the top 15% is 25.27.  

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