A, B & C form a triangle where

Mathematics

1 answer:

andrew-mc [135]3 years ago

7 0

Answer:

16.5mm to. 1 decimal place

Step-by-step explanation:

Please check attachment for diagrammatic representation of the triangle.

Since one of the angles of the triangle is 90, this means that we are dealing with a right angled triangle

To find the length of AC, we make use of pythagoras’ theorem which states that the square of the hypotenuse equals the sum of the square of the other two sides. The hypotenuse is the longest side of the triangle which we have as 17.88 mm

Mathematically therefore

17.8^2 = 6.6^2 + AC^2

AC^2 = 17.8^2 - 6.6^2

AC^2 = 283.28

AC = √(273.28)

AC = 16.53 mm

This is 16.5 to 1 decimal place

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MakcuM [25]

Angle 3: 24 degrees- the angle across from it is 24 which makes this one 24 so it’s congruent.
Angle 1 and 4: 78 degrees- on one side of these angles (the line the seperates it running parallel) the angles total to 180 degrees, we take angle 3 which was 24 and subtract that from 180. That equals 156 which we then divide into two because we have two angles left to solve for which makes 78 each.
Angle 2: 71 degrees- We know angle 3 is 24 and we have a written angle as 85. Knowing each side of these angles equals 180 degrees, we add 85 and 24 to get 109. We then will subtract 180 from 109 to get our missing angle which is 71 degrees.

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3 years ago

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Keith_Richards [23]

Answer:

option (2) is correct.

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