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earnstyle [38]
2 years ago
11

Drwa a model that showes each decimal 0.16

Mathematics
1 answer:
Levart [38]2 years ago
8 0
That an easy way to show your work

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Compare the quantities in Column A and Column B.
GaryK [48]

The y-intercept of 2y = 3x - 4 and the y-intercept of 4x - 2y=4 are equal

The equations are given as:

2y = 3x - 4

4x - 2y=4

Make y the subject in both equations

<u>First equation</u>

2y = 3x - 4

y = \frac 32x - 2

<u>Second equation</u>

4x - 2y=4

y = 2x - 2

A linear equation is represented as:

y = mx + b

Where b represents the y-intercept

So: By comparison,

b_1 = 2 --- the y-intercept of the first equation

b_2 = 2 --- the y-intercept of the second equation

2 = 2.

Hence, the y-intercept of 2y = 3x - 4 and the y-intercept of 4x - 2y=4 are equal

Read more about y-intercepts at:

brainly.com/question/4015585

6 0
2 years ago
6
GalinKa [24]

Answer:

I don't know sorry

sorry

Step-by-step explanation:

I don't know sorry

sorry

3 0
2 years ago
Let X denote the length of human pregnancies from conception to birth, where X has a normal distribution with mean of 264 days a
Kaylis [27]

Answer:

Step-by-step explanation:

Hello!

X: length of human pregnancies from conception to birth.

X~N(μ;σ²)

μ= 264 day

σ= 16 day

If the variable of interest has a normal distribution, it's the sample mean, that it is also a variable on its own, has a normal distribution with parameters:

X[bar] ~N(μ;σ²/n)

When calculating a probability of a value of "X" happening it corresponds to use the standard normal: Z= (X[bar]-μ)/σ

When calculating the probability of the sample mean taking a given value, the variance is divided by the sample size. The standard normal distribution to use is Z= (X[bar]-μ)/(σ/√n)

a. You need to calculate the probability that the sample mean will be less than 260 for a random sample of 15 women.

P(X[bar]<260)= P(Z<(260-264)/(16/√15))= P(Z<-0.97)= 0.16602

b. P(X[bar]>b)= 0.05

You need to find the value of X[bar] that has above it 5% of the distribution and 95% below.

P(X[bar]≤b)= 0.95

P(Z≤(b-μ)/(σ/√n))= 0.95

The value of Z that accumulates 0.95 of probability is Z= 1.648

Now we reverse the standardization to reach the value of pregnancy length:

1.648= (b-264)/(16/√15)

1.648*(16/√15)= b-264

b= [1.648*(16/√15)]+264

b= 270.81 days

c. Now the sample taken is of 7 women and you need to calculate the probability of the sample mean of the length of pregnancy lies between 1800 and 1900 days.

Symbolically:

P(1800≤X[bar]≤1900) = P(X[bar]≤1900) - P(X[bar]≤1800)

P(Z≤(1900-264)/(16/√7)) - P(Z≤(1800-264)/(16/√7))

P(Z≤270.53) - P(Z≤253.99)= 1 - 1 = 0

d. P(X[bar]>270)= 0.1151

P(Z>(270-264)/(16/√n))= 0.1151

P(Z≤(270-264)/(16/√n))= 1 - 0.1151

P(Z≤6/(16/√n))= 0.8849

With the information of the cumulated probability you can reach the value of Z and clear the sample size needed:

P(Z≤1.200)= 0.8849

Z= \frac{X[bar]-Mu}{Sigma/\sqrt{n} }

Z*(Sigma/\sqrt{n} )= (X[bar]-Mu)

(Sigma/\sqrt{n} )= \frac{(X[bar]-Mu)}{Z}

Sigma= \frac{(X[bar]-Mu)}{Z}*\sqrt{n}

Sigma*(\frac{Z}{(X[bar]-Mu)})= \sqrt{n}

n = (Sigma*(\frac{Z}{(X[bar]-Mu)}))^2

n = (16*(\frac{1.2}{(270-264)}))^2

n= 10.24 ≅ 11 pregnant women.

I hope it helps!

6 0
2 years ago
Dan recently bought a new mountain bike for $550. His friend works
Wittaler [7]
$990
550 x .80 = 440
$550 + $440 = $990
8 0
3 years ago
The____ function is the most basic function in a family of functions
docker41 [41]
The answer is: parent function
7 0
3 years ago
Read 2 more answers
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