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2 years ago

Total slack is calculated by ____

1 answer:

8 0

Total slack is calculated by the late finish minus early finish and the late start minus the early start

<h3>What is the total slack?</h3>

Total slack is simply the amount of time taken for a task to be delayed before the project finish date is delayed. It can be positive or negative.

It is calculated as the calculated as the value of the Late Finish minus the Early Finish field, and the Late Start minus the Early Start field.

Total slack = Late finish - early finish + late start - early start

Thus, the total slack is calculated by the late finish minus early finish and the late start minus the early start.

Learn more about slack time here:

brainly.com/question/13278483

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What are the ordered pairs of the

OlgaM077 [116]

Answer:

The two points solutions to the system of equations are: (2, 3) and (-1,6)

Step-by-step explanation:

These system of equations consists of a parabola and a line. We need to find the points at which they intersect:

$x^2-2x+3=-x+5\\x^2-2x+x+3-5=0\\x^2-x-2=0\\(x-2)(x+1)=0$

Since we were able to factor out the quadratic expression, we can say that the x-values solution of the system are:

x = 2 and x = -1

Now, the associated y values we can get using either of the original equations for the system. We pick to use the linear equation for example:

when x = 2 then $y=-(2)+5=3$

when x= -1 then $y=-(-1)+5=6$

Then the two points solutions to the system of equations are: (2, 3) and (-1,6)

6 0

3 years ago

An analyst in Bank of America, Santa Clara University Branch, believes that on Mondays customers arrive at the bank with rate 50

Aleksandr-060686 [28]

Answer:

0.0821

Step-by-step explanation:

If the arrival rate is 50 customers per hour (60 minutes), then the expected number of customers in 3 minutes is:

$\lambda=\frac{50}{60}*3\\ \lambda=2.5\ customers/3\ minutes$

Assuming a Poisson distribution with 2.5 customers per 3 minutes, the probability that zero customers arrive for 3 minutes is:

$P(x=k)=\frac{\lambda^k*e^{-\lambda}}{k!}\\P(x=0)=\frac{2.5^0*e^{-2.5}}{0!}\\ P(x=0)=0.0821$

The probability that the bank stays empty for three minutes is 0.0821.

6 0

3 years ago

Pls help with this (im not trying to be annoying)

ss7ja [257]

C(8)=29 you have to plug in 8 for n in the equation and solve. Hope this helps!!!

5 0

3 years ago

This question is like impossible idk

7nadin3 [17]

If the problem was written x + 4x. We would know to add like the coefficients together and get 5x same thing with the radicals.

$\sqrt{3} + 4 \sqrt{3} = 5 \sqrt{3}$

3 0

3 years ago

8558 rounded to nearest hundred

olasank [31]

8,600 is the answer good sir

7 0

3 years ago

Read 2 more answers