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neonofarm [45]
1 year ago
7

Q.2 - The graph shows the number of paintballs a machine launches, y, in x seconds:

Mathematics
2 answers:
Vesna [10]1 year ago
5 0

Answer:

c

Step-by-step explanation:

Wittaler [7]1 year ago
3 0
The answer is c hope this help norc3:
You might be interested in
Attempt
Pachacha [2.7K]

Answer:

Yes, the triangles are similar by SAS

Step-by-step explanation:

Looking at the picture, we see that there are two triangles with side lengths of different sides. We can deduce that the scale factor is 1 2/3, because 8 divided by 4.8 is 1 2/3, and 10 divided by 6 is the same. Now that we have clarified that the triangles share the same scale factor, we notice that the angle is also the same, as mentioned in the picture. This leads us to say that the triangles are similar by the SAS similarity theorem (Side, Angle, Side). I hope this helped and please don't hesitate to reach out with more questions!

4 0
3 years ago
Carmine paid an electrician x dollars per hour for a 5-hour job plus $70 for parts. The total charge was $320. Which equation ca
pentagon [3]
Division is the answer
4 0
3 years ago
Let A and B be sets with cardinal numbers , n(A) = a and n(B) = b respectively . Decide whether the statement is true or false.
olya-2409 [2.1K]

Answer:

True

Step-by-step explanation:

A\cup B=A\cup(A-B)\\\\A\ and\ A-B\ are\ disjoint\ that\ means\ there\ is\ no\ common\ element\ in\ these\ two.\\\\n(A\cup B)=n(B\cup(A-B))\\\\n(A\cup B)=n(B)+n(A-B)\ \ \ \ \ \ \ as\ for\ disjoint\ set\ P,Q\ n(P\cup Q)=n(P)+n(Q)\\\\(n(P-Q)=n(P)-n(P\cap Q))\\\\n(AUB)=n(B)+n(A-B)\\\\n(AUB)=n(B)+n(A)-n(A\cap B)\\\\n(AUB)=n(A)+n(B)-n(A\cap B)\\\\Hence\ given\ statement\ is\ true

4 0
3 years ago
Convert the fraction 5/8 to decimal using long division method
erma4kov [3.2K]
1/8=0.125
0.625*5=0.625
Or
1/2=0.5
0.5/2=1.25
1.25/2=0.125
Which is 1/8
7 0
3 years ago
Integration of the following function
DerKrebs [107]

Answer: None of the above

Step-by-step explanation:

Given

\frac{\mathrm{d} \bar{c}}{\mathrm{d} x}=-6x^{-2}+\frac{1}{6}

d\bar{c}=\left (  -6x^{-2}+\frac{1}{6}\right )dx

Now, integrating both sides

\int d\bar{c}=\int \left (  -6x^{-2}+\frac{1}{6}\right )dx

\bar{c}=-6\frac{x^{-2+1}}{-2+1}+\frac{1}{6}x+k_1

\bar{c}=6x^{-1}+\frac{1}{6}x+k_1

6 0
3 years ago
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