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3 years ago

What is the reference angle for 300°

Mathematics

1 answer:

kherson [118]3 years ago

4 0

I looked it up on google and got 2.6 I have no clue if it’s right sorry if you get it wrong

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Solve for z. z³ = 64 Enter your answer in the box. z =

zlopas [31]

Answer:

z³ = 64

z³=4³

since power is equal, base will be same

z=4

Step-by-step explanation:

6 0

2 years ago

6n + 9 = -3 - 21 - 6

denis23 [38]

$6n+9=-3-21-6$
subtract the numbers: $-3-21-6=-30$
$6n+9=-30$
subtract 9 from both sides
$6n+9-9=-30-9$
simplify
$6n=-39$
divide both sides by 6
$\frac{6n}{6}= \frac{-39}{6}$
$n= \frac{-13}{6}$
decimal $n=-6.5$
Hope this helps :)

3 0

2 years ago

Write the ratio of thirteen-year-olds to fourteen-year-olds in all three forms.

ludmilkaskok [199]

Answer:

13:14

13 to 14

13/14

Step-by-step explanation:

there are three ways to write ratios, with a colon ( : ), with the word "to", and as a fraction 13/14. ❤

6 0

2 years ago

Read 2 more answers

Pls help me solve this

sammy [17]

Answer:

4 kg of sugar would contain $1.2 \times 10^9$ crystals.

Step-by-step explanation:

Given that 3kg of sugar contains 9 × 10⁸ crystals, let "x" represent the number of sugar crystals 4kg of sugar would contain.

Thus, set up a proportion as follows:

3 kg : 9 × 10⁸ = 4 kg : x

$\frac{3}{9 \times 10^8} = \frac{4}{x}$

Solve for x. Cross multiply.

$3 \times x = 9 \times 10^8 \times 4$

$3x = 36 \times 10^8$

$3x = 3.6 \times 10^9$

Divide both sides by 3

$\frac{3x}{3} = \frac{3.6 \times 10^9}{3}$

$x = 1.2 \times 10^9$

4 kg of sugar would contain $1.2 \times 10^9$ crystals.

5 0

2 years ago

Factor completely.<br> (X^2+ x – 6)(2x^2 + 4x) =<br> What’s the answer

lyudmila [28]

Answer:

(X^2+x−6)⋅2x(x+2

Step-by-step explanation:

7 0

3 years ago