<u>Given</u><u> </u><u>info:</u><u>-</u>If the radius of a right circular cylinder is doubled and height becomes 1/4 of the original height.
Find the ratio of the Curved Surface Areas of the new cylinder to that of the original cylinder ?
<u>Explanation</u><u>:</u><u>-</u>
Let the radius of the right circular cylinder be r units
Let the radius of the right circular cylinder be h units
Curved Surface Area of the original right circular cylinder = 2πrh sq.units ----(i)
If the radius of the right circular cylinder is doubled then the radius of the new cylinder = 2r units
The height of the new right circular cylinder
= (1/4)×h units
⇛ h/4 units
Curved Surface Area of the new cylinder
= 2π(2r)(h/4) sq.units
⇛ 4πrh/4 sq.units
⇛ πrh sq.units --------(ii)
The ratio of the Curved Surface Areas of the new cylinder to that of the original cylinder
⇛ πrh : 2πrh
⇛ πrh / 2πrh
⇛ 1/2
⇛ 1:2
Therefore the ratio = 1:2
The ratio of the Curved Surface Areas of the new cylinder to that of the original cylinder is 1:2
<h2> 4(x - 8) + 10 = -10</h2><h2 />
Start by subtracting 10 from both sides.
This gives us 4x - 32 = -20.
Now add 32 to both sides to get 4x = 12.
Now divide both sides by 3 to get <em>x = 3</em>.
Answer: primeter is 20
Area :
Step-by-step explanation:
Height : 4
Base : 6
Prim - 6+6+4+4=20
Area - 6x4=24
Answer:
H = 35
Step-by-step explanation
21 / 3 is 7 so multiply 7 by 5 to get 35. So 35 is equal to H.
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