Let the angle of elevation is x and the height of the rocket from the ground is y
tanx = y/15
by differentiating both sides with respect to T
sec²x·dx/dt = (dy/dt)/15
at y = 30 , the hypotenuse of the triangle = 15√5
sec²x=(15√5/15)²=5
5 dx/dt = 11/15
dx/dt = 11/75 rad/sec
Answer:
-1.5 + 4.2
Step-by-step explanation:
Since there is no negative sign,the sign would change.
So it will be -1.5+4.2
Answer:
c
Step-by-step explanation:
1.) a.) 12 / 6 = 2
b.) 3 / 2 = 1.5
c.) 16 / 8 =2
d.) Positive
2.) 0 = 0
2 = 13
4 = 26
6 = 39
8 = 52
10 = 65
a.) $6.50
b<span>.) Is increasing
c.) </span>Positive
I believe it's B.
If I'm wrong tell me so I can see what I did wrong.
