In linear equation, The value of the r is a P-q-s.
According to the statement
We have to find that the value of the r .
So, For this purpose, we know that the
The definition of a linear equation is an algebraic equation in which each term has an exponent of one and the graphing of the equation results in a straight line.
From the given information:
The equation is a :
P=q+r+s
This a type of the linear equation then
P=q+r+s
Now, rearrange the terms
P-q-s = r
Then the value of the r is
r = P-q-s .
So, In linear equation, The value of the r is a P-q-s.
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Answer:
8/-7
Step-by-step explanation:
using the equation: y₂-y₁/x₂-x₁
10-2/0-7 = 8/-7
Answer:
f(3π/4) = -π
A = π
b = 2
Step-by-step explanation:
Given that the function follows the form: f(x) = A sin(bx), then f(0) = 0. Given that the period is π, then at x = π/4 the function reaches a maimum, at x = π/2, f(x) = 0, and at x = 3π/4, f(x) reaches a minimum, which have to be π*(-1) = -π
Given the general equation: f(x) = A sin(bx), its period is calculated as:
period = 2π/b
which is equal to π, then:
2π/b = π
b = 2
Replacing x = π/4 into the equation of the function, we get:
A sin(2(π/4)) = π
A sin(π/2) = π
A = π
I hope this helps you
slope = 5-0/-6-(-3)= -5/3
(0,0)
m.(x1-x)=y1-y
-5/3.(0-x)=0-y
5x= -3y
5x+3y=0
