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iVinArrow [24]
3 years ago
8

A factory worker conducted test on a random sample of 150 products. Of the products tested, 2 were found to have defects. Based

on this information, how many products in a batch of 3,000 are likely to be defective?
Mathematics
1 answer:
nata0808 [166]3 years ago
5 0

Answer:

about 1 or more is my hypothesis

Step-by-step explanation:

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60 boys at a summer camp were asked to complete a survey about their favorite outdoor activity. 18 boys chose biking and 29 boys
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First youll want to add 18 and 29. which gives you 43. then you’ll want to find out how much is 29 people percentage wise. so you’ll do 29/43 which gives you 67.44% if it’s answer choices. you round it to the most whole number if they don’t use decimals.
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Selena and Drake are evaluating the expression , when . Selena's Work Drake's Work Who is correct and why? Selena is incorrect b
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Answer:

Selena is correct because she simplified correctly and then evaluated correctly after substituting the values for the variables.

I did this lesson i asked my teacher to help me but i did this problem on my own so i hope its right :)

Step-by-step explanation:

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3 years ago
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2 years ago
James invests $5,000 at an annual rate of 8% simple interest for 7 years. How much is in the account
borishaifa [10]

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Step-by-step explanation:

6 0
3 years ago
A 6m ladder leans against a wall. The bottom of the ladder is 1.3m from the wall at time =0sec and slides away from the wall at
icang [17]

Answer:

- 0.100

Step-by-step explanation:

Length of the ladder,  H = 6 m

Distance at the bottom from the wall, B = 1.3 m

Let the distance of top of the ladder from the bottom at the wall is P

Thus,

from  Pythagoras theorem,

B² + P² = H²    .

or

B² + P² = 6²          ..............(1)      [Since length of the ladder remains constant]

at B = 1.3 m

1.3² + P² = 6²

or

P² = 36 - 1.69

or

P² = 34.31

or

P = 5.857

Now,

differentiating (1)

2B(\frac{dB}{dt})+2P(\frac{dP}{dt})=0

at t = 2 seconds

change in B = 0.3 × 2= 0.6 ft

Thus,

at 2 seconds

B = 1.3 + 0.6 = 1.9 m

therefore,

1.9² + P² = 6²

or

P = 5.69 m

on substituting the given values,

2(1.9)(0.3) + 2(5.69) × (\frac{dP}{dt}) = 0

or

1.14 + 11.38 × (\frac{dP}{dt}) = 0

or

11.38 × (\frac{dP}{dt}) = - 1.14

or

(\frac{dP}{dt}) = - 0.100

here, negative sign means that the velocity is in downward direction as upward is positive

5 0
3 years ago
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