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1 year ago

Which transformations could have occurred to map triangle ABC triangle A^ * B^ n C^ prime

1 answer:

3 0

Reflection and dilation is the transformation which will occur to map triangle ABC triangle to A^ * B^ n C^ prime.

<h3>What is a Triangle?</h3>

This refers to a plane figure which has features such as three angles and three sides.

Reflection and dilation involves flipping and enlargement/reduction respectively which gives rise to the sides being changed.

Read more about Triangle here brainly.com/question/1058720

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What's The scientific notation for 42,000

tester [92]

I think it's (4.2X10^3)

5 0

2 years ago

Read 2 more answers

Last answer option is

wel

statements 1, 3, 4 are correct

6 0

3 years ago

there are 4 aces and 4 kings in a standard deck of 52 cards. you picking card random. what is the probability of selecting an ac

Mkey [24]

Probability of an Ace= 4/52
Probability of a King = 4/52

Probability of an Ace or a King = P(Ace) + P(King)
=4/52 +4/52
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8 0

3 years ago

Solve the equation: <br> 8y - 3 = бу + 17

balandron [24]

Hey!

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Steps To Solve:

8y - 3 = бу + 17

~Subtract 8y to both sides

8y - 3 - 8y = бу + 17 - 8y

~Simplify

-3 = -2y + 17

~Subtract 17 to both sides

-3 - 17 = -2y + 17 - 17

~Simplify

-20 = -2y

~Divide -2 to both sides

-20/-2 = -2y/-2

~Simplify

10 = y

------------------------------------------------

Hence, the answer is $\Large\boxed{\mathsf{y~=~10}}$

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Hope This Helped! Good Luck!

3 0

2 years ago

Read 2 more answers

consider the following scenario: Assume daily protein intake values in a population of athletes are known to have a standard dev

Kipish [7]

Answer:

The 95% confidence interval for the population mean daily protein intake is between 69.97g and 84.03g.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.95}{2} = 0.025$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.025 = 0.975$ , so $z = 1.96$

Now, find M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

$M = 1.96*\frac{58.6}{\sqrt{267}} = 7.03$

The lower end of the interval is the sample mean subtracted by M. So it is 77 - 7.03 = 69.97g.

The upper end of the interval is the sample mean added to M. So it is 77 + 7.03 = 84.03g.

The 95% confidence interval for the population mean daily protein intake is between 69.97g and 84.03g.

5 0

3 years ago