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1 year ago

Solve the system of equations 2x-2y=-14 and 3x-y=-1 by combining the equations.

Mathematics

1 answer:

Veseljchak [2.6K]1 year ago

7 0

The solution to the system of equations is x = 3 and y = 10

<h3>How to solve the equations?</h3>

The system is given as:

2x-2y=-14

3x-y=-1

Multiply (1) by 1 and (2) by 2

So, we have:

1(2x-2y=-14)

2(3x-y=-1 )

This gives

2x - 2y=-14

6x - 2y=-2

Subtract the equations

-4x = -12

Divide by -4

x = 3

Substitute x = 3 in 3x-y=-1

3(3)-y=-1

Evaluate

9 - y = -1

Solve for y

y = 10

Hence, the solution to the system of equations is x = 3 and y = 10

Read more about system of equations at:

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3 years ago

Since an instant replay system for tennis was introduced a a major tournament, men challenged 1390 referee calls, with the resul

alexandr402 [8]

Answer:

H0: μm − μw = 0

against the claim

Ha: μm − μw ≠ 0

Since the calculated value of z= 0.6177 does not lie in the critical region the null hypothesis is accepted that men and women have equal success in challenging calls.

Step-by-step explanation:

1) Let the null and alternate hypothesis be

H0: μm − μw = 0

against the claim

Ha: μm − μw ≠ 0

2) The significance level is set at 0.05

3) The critical region is z > + 1.96 and z< -1.96

4) The test statistic

Z= p1-p2/ sqrt [pcqc( 1/n1+ 1/n2)]

Here p1= 411/ 1390= 0.2956 and p2= 213/753=0.2829

pc = 411+ 213/1390+753

pc=624/2143

pc= 0.2912

qc= 1-pc= 1-0.2912=0.7088

5) Calculations

Z= p1-p2/ sqrt [pcqc( 1/n1+ 1/n2)]

z= 0.2956-0.2829/√ 0.2912*0.7088( 1/1390+ 1/753)

z= 0.0127/ √0.2064 (0.00204)

z= 0.0127/0.02056

z= 0.6177

6) Conclusion

Since the calculated value of z= 0.6177 does not lie in the critical region the null hypothesis is accepted that men and women have equal success in challenging calls.

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Need help with angle solving

laiz [17]

Step-by-step explanation:

corresponding angles (CA)

Alternative interior angles (AIA)

co interior angles (CIA)

question 1 angles =

5 + 3 = 180 ( CIA)

83⁰ + 3 = 180

angle 3 = 180 - 83⁰

angle 3 = 97

angle 8 = angle 3.... CA

angle 8 = angle 16 ....CA

ANGLE 16 = ANGLE 12.....CA

angle 5 = angle 13 ....CA

ANGLE 3 = Angle 6......AIA

ANGLE 5 = ANGLE 4.......AIA

ANGLE 4 = ANGLE 7......CA

ANGLE 6 = ANGLE 1......CA

ANGLE 13 = ANGLE 9......CA

ANGLE 12 = ANGLE 14.....AIA

ANGLE 13 = ANGLE 11.....AIA

ANGLE 14 = ANGLE 10.......CA

ANGLE 11 = ANGLE 15

NOW JUST PUT THE VALUES GIVEN IN QUESTION AND AT THE TOP OF MY ANSWER IN EACH CASE AND UR DONE.....

QUESTION 2 :

ANGLE 1 = ANGLE 7 .......AIA

2X + 40 = 6X - 20

40 + 20 = 6X - 2X

60 = 4X

60/4 = X

15⁰ = X

SO, ANGLE 7 = 6× 15 -20 = 90 - 20 = 70⁰

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ANGLE 7 = ANGLE 3 ......CA

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70 + ANGLE 6 = 180⁰

ANGLE 6 = 180 - 70⁰ = 110⁰

angle 2 = Angle 6

ANGLE 2 = ANGLE 8.....AEA ALTERNATIVE EXTERIOR ANGLE

ANGLE 8 = ANGLE 4

NOW, JUST PUT THE VALUES I HAVE WRITTEN ABOVE ACCORDINGLY IN EACH CASE....

Did I really jst got 15 points for this (ノ｀Д´)ノ彡

HEHEEE JK:)

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